Order is not important, so this is a combination problem.
There are 5 odd numbers from 1 to 10.
n(E) = 5C2 = 5*4/2*1 = 10
n(S) = 10C2 = 10*9/2*1 = 45
P = n(E)/n(S) = 10/45 = 2/9
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The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
Since there are only odd & even numbers, the probability is 1/2 or 0.5.
The probabiliy of selecting odd or prime numbers from 1 to 50. First find out the probability of selecting odd numbers : 25/50 is 1/2. Lets find out the probability of selecting prime numbers: 15 / 50 . so, total is 40/ 50 is 0.82.
The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54