Order is not important, so this is a combination problem.
There are 5 odd numbers from 1 to 10.
n(E) = 5C2 = 5*4/2*1 = 10
n(S) = 10C2 = 10*9/2*1 = 45
P = n(E)/n(S) = 10/45 = 2/9
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
Since there are only odd & even numbers, the probability is 1/2 or 0.5.
In the range of 1 to 10, there are five odd numbers: 1, 3, 5, 7, and 9. Since there are a total of 10 numbers, the probability of selecting an odd number is the number of odd outcomes divided by the total outcomes. This gives us a probability of 5/10, which simplifies to 1/2 or 50%.
The probabiliy of selecting odd or prime numbers from 1 to 50. First find out the probability of selecting odd numbers : 25/50 is 1/2. Lets find out the probability of selecting prime numbers: 15 / 50 . so, total is 40/ 50 is 0.82.
Thereare 50 odd numbers and 50 even numbers in that range, so the probability is 1 out of 2
The probability of spinning the spinner and landing on an odd number depends on the number of odd numbers on the spinner and the total number of numbers on the spinner. If there are 3 odd numbers on the spinner and a total of 6 numbers, then the probability of landing on an odd number is 3/6, which simplifies to 1/2 or 50%.
If you have an equal amount of odd and even numbers in a determined sample space, the probability of choosing and odd number is 1/2 (.5).
Since there are only odd & even numbers, the probability is 1/2 or 0.5.
I'm assuming you multiply the numbers rolled. Thus the rules of even and odd numbers come into play. The only way to get an odd product is to roll two odd numbers. The probability desired is 1 minus the probability of rolling two odd numbers. The odds of rolling an odd number is 1/2. Since the rolls are independent events, the odds of rolling two odd numbers is (1/2)2 = 1/4 So the probability of getting an even product is: 1 - 1/4 = 3/4
In the range of 1 to 10, there are five odd numbers: 1, 3, 5, 7, and 9. Since there are a total of 10 numbers, the probability of selecting an odd number is the number of odd outcomes divided by the total outcomes. This gives us a probability of 5/10, which simplifies to 1/2 or 50%.
If you chose the number out of an equal numberof odd and even numbers then it would be 50% chance. Like if you chose an odd number out of the numbers from 1 to 100
The probabiliy of selecting odd or prime numbers from 1 to 50. First find out the probability of selecting odd numbers : 25/50 is 1/2. Lets find out the probability of selecting prime numbers: 15 / 50 . so, total is 40/ 50 is 0.82.
To answer this problem you first see how many even and odd numbers there are. There are 3 odd and 3 even. so the fraction for even and odd is 3/6 so then in simplified form it is 1/2. If they ask to express the probability as a decimal number it would be .5 or.50
The answer depends on how many dice you roll and how often. If you roll four dice once, the probability of getting a double AND two odd numbers is 264/1296 = 11/54
From 75 to 100 (inclusive), there are 26 numbers, and 13 of them are odd.The probability of picking an odd number is 13/26 = 50%.
The probability is .5 since half the numbers are even and half are odd.