When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
The Principle of Dominance states that some alleles are dominant and some alleles are recessive. The dominant trait dominates or presents the expression of the recessive trait. Thus, for round seed: (capital) R - round (small) r - wrinkled RR - pure round Rr - hybrid round rr - pure wrinkled
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
rr cubed is r6rr cubed is r6rr cubed is r6rr cubed is r6
The QTc Fredericia is calculated using the formula: QTc = QT / √(RR), where QT is the measured QT interval in milliseconds and RR is the RR interval in seconds. First, convert the RR interval from milliseconds to seconds by dividing by 1000. Then, plug the QT and RR values into the formula to obtain the corrected QT interval. This adjustment accounts for heart rate variations, providing a more accurate assessment of cardiac repolarization.
If round seeds are dominant and wrinkled seeds are recessive, then in a cross between two plants with heterozygous genotypes (Rr), 75% of the offspring will have round seeds (25% RR, 50% Rr) and 25% will have wrinkled seeds (rr).
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
A pea plant with wrinkled seeds must have two recessive alleles for the wrinkled seed trait (rr). This means that both of its parents must have contributed a copy of the recessive allele for the plant to exhibit wrinkled seeds.
The genotype is always the "gene formula", in this case Rr.The phenotype is the expression of the genes (how the animal or plant looks, functions, or behaves). In this case, it's a bit hard to say what the phenotype would be without knowing what R is!If the question is about garden peas, and if R is the dominant allele responsible for round seeds, and r the recessive allele producing wrinkled seeds, then the genotype Rr will produce the phenotype of the dominant allele, i.e. round seeds.
In pea plants, round seeds are dominant over wrinkled seeds. This means that if a pea plant has one allele for round seeds and one allele for wrinkled seeds, it will produce round seeds because the round allele is dominant.
The Principle of Dominance states that some alleles are dominant and some alleles are recessive. The dominant trait dominates or presents the expression of the recessive trait. Thus, for round seed: (capital) R - round (small) r - wrinkled RR - pure round Rr - hybrid round rr - pure wrinkled
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
If they are expressing the trait, 100%, as their genotypes would be, rr X rr If they both carry the trait and it is dominated, Rr X Rr, then the probability would be, 25% of their child expressing the trait.
well it depends on the letters that you are given, recessive alleles are ALWAYS lower case.An example answer would be: ss, where s would represent the recessive allele.
rr
Round seed shape in peas is an example of a trait controlled by a dominant allele because the presence of even one copy of the dominant allele results in the expression of the round seed shape phenotype. This means that individuals with either two dominant alleles (RR) or one dominant and one recessive allele (Rr) will have round seeds, while individuals with two recessive alleles (rr) will have wrinkled seeds.