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In a cross between two heterozygous pea plants (Rr x Rr), where "R" represents the dominant allele for smooth seeds and "r" represents the recessive allele for wrinkled seeds, the probability of producing wrinkled seeds (rr) can be determined using a Punnett square. The genotype ratio from this cross is 1 RR : 2 Rr : 1 rr. Therefore, the probability of producing wrinkled seeds (rr) is 1 out of 4, or 25%.
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What is the probability that two heterozygous parents would have an offspring that produced round seeds from Mendel?
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
What is the probability that the offspring will have wrink seeds?
To determine the probability of offspring having wrinkled seeds, we need to know the genetic makeup of the parents. If we assume that wrinkled seeds are a recessive trait (represented by "r") and smooth seeds are dominant (represented by "R"), then the probability depends on the genotypes of the parents. For example, if both parents are heterozygous (Rr), there is a 25% chance that the offspring will inherit the wrinkled seed trait (rr). Without specific parental genotypes, we cannot provide an exact probability.
What is the possibility that two heterozygous parents would have an offspring that produced round seeds?
In pea plants, the round seed trait (R) is dominant over the wrinkled seed trait (r). If both parents are heterozygous (Rr), the possible offspring genotypes are RR, Rr, and rr, with a 75% chance of producing round seeds (RR or Rr) and a 25% chance of producing wrinkled seeds (rr). Therefore, there is a 75% possibility that two heterozygous parents would have an offspring that produces round seeds.
What is the principle of dominance?
The Principle of Dominance states that some alleles are dominant and some alleles are recessive. The dominant trait dominates or presents the expression of the recessive trait. Thus, for round seed: (capital) R - round (small) r - wrinkled RR - pure round Rr - hybrid round rr - pure wrinkled
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
What is the probability that two heterozygous parents would have an offspring that produced round seeds from Mendel?
When both parents are heterozygous for seed shape (Rr, where R is the allele for round seeds and r is the allele for wrinkled seeds), the probability of producing an offspring with round seeds can be determined using a Punnett square. The possible genotypes are RR, Rr, Rr, and rr. Thus, there are three combinations (RR and Rr) that result in round seeds out of four total combinations. Therefore, the probability of having an offspring with round seeds is 3 out of 4, or 75%.
What is the probability that the offspring will have wrink seeds?
To determine the probability of offspring having wrinkled seeds, we need to know the genetic makeup of the parents. If we assume that wrinkled seeds are a recessive trait (represented by "r") and smooth seeds are dominant (represented by "R"), then the probability depends on the genotypes of the parents. For example, if both parents are heterozygous (Rr), there is a 25% chance that the offspring will inherit the wrinkled seed trait (rr). Without specific parental genotypes, we cannot provide an exact probability.
What is the possibility that two heterozygous parents would have an offspring that produced round seeds?
In pea plants, the round seed trait (R) is dominant over the wrinkled seed trait (r). If both parents are heterozygous (Rr), the possible offspring genotypes are RR, Rr, and rr, with a 75% chance of producing round seeds (RR or Rr) and a 25% chance of producing wrinkled seeds (rr). Therefore, there is a 75% possibility that two heterozygous parents would have an offspring that produces round seeds.
Round seeds are dominate to wrinkled seeds What percentage of the offspring will be round?
If round seeds are dominant and wrinkled seeds are recessive, then in a cross between two plants with heterozygous genotypes (Rr), 75% of the offspring will have round seeds (25% RR, 50% Rr) and 25% will have wrinkled seeds (rr).
A pea plant with round seeds has the genotype Rr you cross this plant with a wrinkled seed plant genotype rr what is the probability that the offspring will have wrinkled seeds?
To figure this out, use a Punnet Square.First, set up a test cross, like this:Rr x rrThis shows what you are crossing. Now you can make a Punnet Square.R rr Rr rr There is a 50/50 chance that the corn plant will have thegenotype rr.r Rr rr
What was the probability that two heterozygous parents would have an offspring that produced round seeds?
If both parents are heterozygous for seed shape (Rr), their offspring would have a 75% chance of producing round seeds (3 out of 4 possible combinations), assuming round seeds (R) are dominant over wrinkled seeds (r).
What jeans does a pea plant with wrinkled seeds have?
A pea plant with wrinkled seeds must have two recessive alleles for the wrinkled seed trait (rr). This means that both of its parents must have contributed a copy of the recessive allele for the plant to exhibit wrinkled seeds.
What gametes will be produced by each parent RR x rr?
The genotype is always the "gene formula", in this case Rr.The phenotype is the expression of the genes (how the animal or plant looks, functions, or behaves). In this case, it's a bit hard to say what the phenotype would be without knowing what R is!If the question is about garden peas, and if R is the dominant allele responsible for round seeds, and r the recessive allele producing wrinkled seeds, then the genotype Rr will produce the phenotype of the dominant allele, i.e. round seeds.
In pea plants are round or wrinkled seeds dominant?
In pea plants round seeds are dominant to wrinkled. So to have round seeds you either will have two dominant alleles (homozygous dominant) or one dominant and one recessive allele (heterozygous)
What is the principle of dominance?
The Principle of Dominance states that some alleles are dominant and some alleles are recessive. The dominant trait dominates or presents the expression of the recessive trait. Thus, for round seed: (capital) R - round (small) r - wrinkled RR - pure round Rr - hybrid round rr - pure wrinkled
What is the probability that two heterozygous parents would have an offspring that produced round seeds?
The probability is 3/4 or 75%. If both parents are heterozygous for the seed shape trait (e.g., Rr), there is a 50% chance that each parent will pass on the dominant allele (R) for round seeds to the offspring. The probability of inheriting the dominant allele from both parents and producing round seeds is therefore (1/2) x (1/2) = 1/4 or 25%. Since there are two possible ways to inherit the dominant allele (from either parent), the total probability is 2 x (1/4) = 1/2 or 50%.
What is the probability Two individuals with autosomal recessive trait will have a child with the same trait?
If they are expressing the trait, 100%, as their genotypes would be, rr X rr If they both carry the trait and it is dominated, Rr X Rr, then the probability would be, 25% of their child expressing the trait.
