You will get different answers depending on whether you mean:
7
The answer depends on WHAT is landed: a number cube, a tetrahedral die, some other polyhedron, a spinner?
The answer depends on how many times it is rolled.
The expectation is 50 times.
It is 0.722... recurring.
The experimental probability of a number cube that lands on 5 four times in a twenty toss trial is Pexp(5) = 4/20 = 1/5 = 0.20 = 20%
7
The answer depends on WHAT is landed: a number cube, a tetrahedral die, some other polyhedron, a spinner?
1/2 * 1/6 = 1/12
The question does not say which event the probability is required for!
The answer depends on how many times it is rolled.
The probability of rolling any number on a cube can be represented by the formula: X / the number of variables. Since any cube has 6 sides, the probability of rolling any of the numbers 1 through 6 on the cube, can be represented by the formula: X = 1 / 6 = 16.66% The odds or probability of flipping a coin and landing it on either side can be represented by X = the requested result / the number of variables = 1 /2 = 50% Therefore, given the two questions of probability, there is a much greater chance of landing a coin on "tails" rather than rolling a "4".
1/8
The expectation is 50 times.
It is 0.722... recurring.
A number cube is a six sided figure so I'm going to go with 0%
If the cube is uniformly weighted there is a 1 in 6 chance of any side landing face-up