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In probability questions, the word "or" means add. Assuming the numbers are 1-12, the prime numbers would be 1, 2, 3, 7, and 11. The odd numbers are 1, 3 , 5, 7, 9, and 11. You don't add duplicates when determining probability, so all your options for a prime number or an odd number are 1,2,3, 5, 7, 9, and 11. This means there are 7/12 that are prime or odd, or a probability of 0.5833.
Half
The answer depends on the sum of WHAT!
no.
the probability is 4 out of 6
Since there are 3 prime numbers, 13, 17, and 19, in the range 12 to 19, the probability of throwing a prime number on a fair eight sided die numbered 12 to 19 is 3 in 8.
Even probability: 3/6= 1/2 Odd probability: 3/6= 1/2 (a cube has six sides and normally is numbered 1-6)
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In probability questions, the word "or" means add. Assuming the numbers are 1-12, the prime numbers would be 1, 2, 3, 7, and 11. The odd numbers are 1, 3 , 5, 7, 9, and 11. You don't add duplicates when determining probability, so all your options for a prime number or an odd number are 1,2,3, 5, 7, 9, and 11. This means there are 7/12 that are prime or odd, or a probability of 0.5833.
total numbers taht can be occure=1,2,3,4,5,6 prime number taht can occure in a roll= 2, 3,5 total sample space= n=6 total faverable cases= m=3 P(prime number)=m/n=3/6=1/2 probability of rolling a prime number is 1/2
Half
With a standard 6 faced die, numbered 1 through 6, there are three odd numbers, 1, 3, and 5, of which 3 and 5 are prime, and there is one even prime, 2. The probability, then, of rolling an odd number which is prime is 1 in 3, i.e. 3 or 5 out of a possible result set of 1, 2, 3, 4, 5, and 6.
When a fair die is thrown the probability that a prime number will occur is 2:1
"The probability of getting a prime number in a die is 4/6" Actually there are 3 prime numbers on a die. 2, 3, and 5 are all prime numbers. So this tells you that you have 3 chances it will be a prime number and 3 chances it will not be a prime number. So the probability of getting a prime number on a die would be 3/6 or 1/2.
The probability of getting at least one prime number in two dice is 3/4.
The probability of eventually throwing a prime number is 1. On a single throw, of a fair die, the probability is 1/2.
The answer depends on the sum of WHAT!