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Probability = Chance of Success / Total Chances (Chance of Success + Chance of Failure) There are 4 aces in a 52 card deck and 48 cards that are not aces. Probability of being dealt an ace = 4 / (4 + 48) = 4/52 = .0769 or about 7.7 percent
The odds of any card pulled from an ordinary deck of 52 cards being an Ace is 4 in 52 (4 aces in a deck of 52). This can be reduced to a 1 in 13 chance of any random card pulled from the deck being an Ace (or any other specific value, for that matter). That 13th last card dealt in a hand is no different than picking a random card out of the pack, regardless of what cards you deal before (face down or blindfolded or even face up, it doesn't matter). A more interesting question would be "what would the probability be of ANY of those 13 cards being an Ace?" Any takers?
The probability is 4/52 for the first ace and 3/51 for the second. So the probability of 2 aces is 4/52 x 3/51 = 1/221
In a standard 52 card deck, the probability of drawing an ace is 1/13, and the probability of drawing a diamond is 1/4. The probability of drawing both an ace and a diamond is 1/52.Thus the probability of drawing an ace or a diamond is1/13 + 1/4 - 1/52 = 4/13 or about .308.
The probability of pick a red ace out of a standard deck of cards would be 1/26 because there are two read aces, the ace of diamonds and the ace of hearts.