Let A= getting an ace the first time
and B= getting an ace the second
We are looking to for the probaliity of getting A and B that is P(A and B)
We know P(A and B) = P(A) . P(B|A)
= (4/52) . (3/51) = 1/122 = .00452
NOTE that P(B|A) is the conditional probability of getting an ace the second time given that you got an ace the first time.
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The probability of drawing two Aces from a standard 52 card deck is (4 in 52) times (3 in 51) or (12 in 52851) or (4 in 17617) or about 0.0002271.
A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
The probability of drawing a spade or an ace from a 52 card deck of standard playing cards is 16 / 52 or approximately 30.8%. There are 13 spades in a standard deck of cards. There are four aces in a standard deck of cards. One of the aces is a spade. So, 13 + 4 - 1 = 16 spades or aces to choose from. Since we have a total of 52 cards, the probability of selecting an ace or a spade is 16 / 52 or approximately 30.8%.
Since there are 4 aces is a normal deck of 52 cards, the probability of drawing an ace is 4 in 52, or 1 in 13.