Let A= getting an ace the first time
and B= getting an ace the second
We are looking to for the probaliity of getting A and B that is P(A and B)
We know P(A and B) = P(A) . P(B|A)
= (4/52) . (3/51) = 1/122 = .00452
NOTE that P(B|A) is the conditional probability of getting an ace the second time given that you got an ace the first time.
The probability of drawing two Aces from a standard 52 card deck is (4 in 52) times (3 in 51) or (12 in 52851) or (4 in 17617) or about 0.0002271.
A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
The probability of drawing a spade or an ace from a 52 card deck of standard playing cards is 16 / 52 or approximately 30.8%. There are 13 spades in a standard deck of cards. There are four aces in a standard deck of cards. One of the aces is a spade. So, 13 + 4 - 1 = 16 spades or aces to choose from. Since we have a total of 52 cards, the probability of selecting an ace or a spade is 16 / 52 or approximately 30.8%.
Since there are 4 aces is a normal deck of 52 cards, the probability of drawing an ace is 4 in 52, or 1 in 13.
The probability of drawing two Aces from a standard 52 card deck is (4 in 52) times (3 in 51) or (12 in 52851) or (4 in 17617) or about 0.0002271.
The answer depends on whether aces are high or low. With aces low, the probability is 5/13 on a single random draw.
A pinochle deck consists of 48 cards. Eight of these cards are aces (2 aces per suit * 4 suits = 8 aces). So, for a random drawing from a complete pinochle deck, the probability of drawing an ace is 8/48 = 1/6.
Since there are only four aces in a standard 52 card deck, the probability of being dealt five aces is zero.
The probability of drawing a spade or an ace from a 52 card deck of standard playing cards is 16 / 52 or approximately 30.8%. There are 13 spades in a standard deck of cards. There are four aces in a standard deck of cards. One of the aces is a spade. So, 13 + 4 - 1 = 16 spades or aces to choose from. Since we have a total of 52 cards, the probability of selecting an ace or a spade is 16 / 52 or approximately 30.8%.
There are 52 cards in a deck there are 4 aces and 4 kings which makes a total of 8 kings and aces. Assuming that the deck is full and shuffled the probability of drawing an aces or a king is 8/52 which simplifies to 2/13
there are 4 aces in a deck, and 52 cards, so the probability is 4/52
Since there are 4 aces is a normal deck of 52 cards, the probability of drawing an ace is 4 in 52, or 1 in 13.
Probability of drawing a seven of spades, from a 52 card deck, is 1/52.
The probability is 4/52*3/51 ~= 0.0045 = 0.45%
The probability of drawing one ace from a deck of 52 cards is 13 to 1 as there are 4 aces in a deck of 52 cards. The probability of then taking another ace is then 17 to 1 as there are now 3 aces in a deck of 51 cards. The total probability for the two events in succession would now be: (13 x 17) to (1 x 1) which is 221 to 1.
If you are drawing only two cards, the probability that they will both be aces is one in 221. ( (52 / 4) * (51 / 3) ) If you are drawing all the cards in the deck, one at a time, the probability that you will draw at least two aces in a row is much better than that, but how much better I leave for someone else to answer.