The probability of getting 4 of a kind with 5 dice is: 6 5C4 (1/6)4 (5/6) = 0.0192901..≈ 1.93%
The probability is 1.The probability is 1.The probability is 1.The probability is 1.
The chances of getting 4 of a kind is: 13 * 48! / 52! = 1 in 499,800
The "or" in the statement is addition; so even with one coin the probability of getting a head or a tail when spinning it is 1, and since the probability can never be greater than 1, the answer is 1. Correct. I suspect the questioner means something different. Probability of getting H & H = 1/2x1/2 = 1/4 Probability of getting H & T = 1/2 x 1/2 = 1/4 Probability of getting T & H = 1/2 x 1/2 = 1/4 Probability of getting T & T = 1/2 x 1/2 = 1/4 So probability of getting just 1 head = 1/4 +1/4 = 1/2 Probability of getting 2 heads = 1/4 So probability of getting 1 or 2 heads = 1/2 + 1/4 = 3/4 Probability of not getting a head = 1/4 Similarly for switching heads and tails.
The probability is 1 out of 5
The probability of getting 4 of a kind with 5 dice is: 6 5C4 (1/6)4 (5/6) = 0.0192901..≈ 1.93%
The probability is 1.The probability is 1.The probability is 1.The probability is 1.
The chances of getting 4 of a kind is: 13 * 48! / 52! = 1 in 499,800
If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032If they are fair dice, the probability is 0.0032
The "or" in the statement is addition; so even with one coin the probability of getting a head or a tail when spinning it is 1, and since the probability can never be greater than 1, the answer is 1. Correct. I suspect the questioner means something different. Probability of getting H & H = 1/2x1/2 = 1/4 Probability of getting H & T = 1/2 x 1/2 = 1/4 Probability of getting T & H = 1/2 x 1/2 = 1/4 Probability of getting T & T = 1/2 x 1/2 = 1/4 So probability of getting just 1 head = 1/4 +1/4 = 1/2 Probability of getting 2 heads = 1/4 So probability of getting 1 or 2 heads = 1/2 + 1/4 = 3/4 Probability of not getting a head = 1/4 Similarly for switching heads and tails.
The probability is 1/4
The probability of getting the queen of hearts is 1 in 52, or about 0.01923. The probability of getting any queen is 4 in 52, or about 0.07692. The probability of getting any heart is 13 in 52, or exactly 0.25.
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
The probability is 1 out of 5
The probability of not getting a club is the same as the probability of getting one of the other suits. There are (52-13)=39 such possibilities out of 52. Hence the probability is 39/52=3/4.
The probability of getting a head is 1/2 and if you toss it 4 times, the probability of 4 heads is (1/2)^4=1/16 since the tosses are independent events.
1/6^3