Assuming that it is a fair die, the answer is 5/9.
1 out of 2
5 out of 6
The "or" in the statement is addition; so even with one coin the probability of getting a head or a tail when spinning it is 1, and since the probability can never be greater than 1, the answer is 1. Correct. I suspect the questioner means something different. Probability of getting H & H = 1/2x1/2 = 1/4 Probability of getting H & T = 1/2 x 1/2 = 1/4 Probability of getting T & H = 1/2 x 1/2 = 1/4 Probability of getting T & T = 1/2 x 1/2 = 1/4 So probability of getting just 1 head = 1/4 +1/4 = 1/2 Probability of getting 2 heads = 1/4 So probability of getting 1 or 2 heads = 1/2 + 1/4 = 3/4 Probability of not getting a head = 1/4 Similarly for switching heads and tails.
The probability is 1 out of 5
Assuming that it is a fair die, the answer is 5/9.
The probability is 1/6.
1 out of 2
5 out of 6
The "or" in the statement is addition; so even with one coin the probability of getting a head or a tail when spinning it is 1, and since the probability can never be greater than 1, the answer is 1. Correct. I suspect the questioner means something different. Probability of getting H & H = 1/2x1/2 = 1/4 Probability of getting H & T = 1/2 x 1/2 = 1/4 Probability of getting T & H = 1/2 x 1/2 = 1/4 Probability of getting T & T = 1/2 x 1/2 = 1/4 So probability of getting just 1 head = 1/4 +1/4 = 1/2 Probability of getting 2 heads = 1/4 So probability of getting 1 or 2 heads = 1/2 + 1/4 = 3/4 Probability of not getting a head = 1/4 Similarly for switching heads and tails.
The probability is 1/4
The probability of getting the queen of hearts is 1 in 52, or about 0.01923. The probability of getting any queen is 4 in 52, or about 0.07692. The probability of getting any heart is 13 in 52, or exactly 0.25.
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
The probability is 1 out of 5
The probability is 1.The probability is 1.The probability is 1.The probability is 1.
Assuming the numbers on the die are 1, 2, 3 and 4, the probability is 1.
The probability of not getting a club is the same as the probability of getting one of the other suits. There are (52-13)=39 such possibilities out of 52. Hence the probability is 39/52=3/4.