1 out of 2
5 out of 6
Assuming that it is a fair die, the answer is 5/9.
The theoretical probability of rolling something other than a factor of 6 in one roll is 2/6 or 1/3. So, the probability of rolling something other than a factor of 6 in 100 rolls is (1/3)^100 = 1.94*10-48 And therefore.the probability of rolling a factor of 6 is 1 - Prob(not a factor) = 1 - 1.94*10-48 which is incredibly close to 1.
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
The probability is 1/6.
1 out of 2
5 out of 6
Probability of getting not a yellow sweet if there 3 yellow sweets and 10 blue sweets is 10/13.
Assuming that it is a fair die, the answer is 5/9.
.333
The probability of getting two prime numbers when two numbers are selected at random and without replacement, from 1 to 10 is 2/15.
The theoretical probability of rolling something other than a factor of 6 in one roll is 2/6 or 1/3. So, the probability of rolling something other than a factor of 6 in 100 rolls is (1/3)^100 = 1.94*10-48 And therefore.the probability of rolling a factor of 6 is 1 - Prob(not a factor) = 1 - 1.94*10-48 which is incredibly close to 1.
Answer this Question : Probability of getting 10 heads in a row is(1/2)^10 = 1/1024 = 0.000976 or 0.098 %
The probability of getting 8 heads out of 10 tosses is (10C8)(1/2)^8 (1/2)^2 = 45 / 1024 = 0.0439. It is assumed that the probability of getting a head in a single toss is 1/2. 10C8 = 10 x 9 / 1 x 2 = 45
7/10
The factors of 10 are the numbers that divide 10 evenly: 1, 2, 5 and 10. To answer your question, you have to figure out what the probability of rolling one of these numbers is on a number cube.