Pr(Red queen) = 2/52 = 1/26 = 3.85%
Pr(4 on a die) = 1/6 = 16.67%
Pr(Red queen AND 4 on a die) = 1/26 * 1/6 = 1/156 = 0.64%
2/5
An event can either happen or not happen. If the probability of it happening is 3/5,then the probability of it not happening is 2/5.
There are two black 7's and two red queen's in a standard deck of playing cards. The probability of drawing a black 7 is 2 in 52, or 1 in 26, or about 0.038. The probability of drawing a red queen from the remaining 51 cards is 2 in 51, or about 0.039. The probability, then, or drawing a black 7 followed by a red queen is (2 in 52) times (2 in 51), which is 4 in 2652, or 2 in 1326, or about 0.00151.
The probability of drawing a red queen in a complete package of playing cards (ignoring jokers) is 1/26 or approximately 3.8%. There are 26 red cards in a deck of 52 cards. There are 2 red queens in those 26 red cards (one queen of diamonds and one queen of hearts). SO: 2 / 52 = 1 / 26 = approximately 3.8%.
The probability of drawing two red cards with replacement is (1 in 2)2 or (1 in 4) or 0.25
2/5
The probability of drawing a red heart is 1 in 4. This is the same as the probability of drawing a heart, as red is included as a superset of hearts.
The probability of getting a diamond and a black seven is zero. Diamonds are red.
An event can either happen or not happen. If the probability of it happening is 3/5,then the probability of it not happening is 2/5.
In a standard deck of 52 cards, there are 13 red cards and four queens. Since one of the red cards is also a queen, there are 16 cards that are either red or a queen. The probability, then, of drawing a red card or a queen is 16 in 52, or 8 in 26, or 4 in 13, or about 0.3077.
There are two black 7's and two red queen's in a standard deck of playing cards. The probability of drawing a black 7 is 2 in 52, or 1 in 26, or about 0.038. The probability of drawing a red queen from the remaining 51 cards is 2 in 51, or about 0.039. The probability, then, or drawing a black 7 followed by a red queen is (2 in 52) times (2 in 51), which is 4 in 2652, or 2 in 1326, or about 0.00151.
2 out of 52
The probability of drawing a red queen in a complete package of playing cards (ignoring jokers) is 1/26 or approximately 3.8%. There are 26 red cards in a deck of 52 cards. There are 2 red queens in those 26 red cards (one queen of diamonds and one queen of hearts). SO: 2 / 52 = 1 / 26 = approximately 3.8%.
If there is 3 blue 2 red and 4 green. What is the probability of getting green?
The probability that two dice rolled will each have the same value is 1 in 6.
The probability of drawing two red cards with replacement is (1 in 2)2 or (1 in 4) or 0.25
Assuming we're drawing two cards, one of which is red and the other is a queen... There are 26 reds/52 = 1/2 chance of red If the first card is not a queen (12/13 chance), the odds of next drawing a queen is 4/51. Total probability is (1/2)(4/51) = 2/51. If the first card was a queen (1/13 chance), the odds of getting another queen is 3/51, for a total of 3/102. Weighted average the two (12/13)*(2/51) + (1/13)*(3/102) = 3.85% Could also do it in reverse order Queen first - 1/13 If first card was red, chance of another red is 25/51. Total probability of 25/13*51. If first card was black, chance of red is 26/51. Total probability of 26/13*51=2/51. Average the two (25/26*52 + 2/102) = 3.81% Add up the probabilities - 7.66% chance