There are factors such as genetic tendencies, age etc which favour male or female offspring so that the probability of a male offspring is not uniformally 1/2.
Next, the question does not specify how many offspring in all, so the possible sequences could be
[any sequence whether or not containing MMM] followed by [MMM] followed by [any sequence whether or not containing MMM].
As the sequence grows longer, the probability that somewhere in the sequence there are 3 male offspring in a row increases.
For 3 offspring, the probability is 1/8 = 0.125
for 8 offspring, the probability is 107/256 = 0.418
The probabilities would need to be weighted together using the proportion of families that have 3 children, 4 children, and so on.
you have a 75% chance
It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.
The probability of getting a heads on the first flip is 1/2. Similarly, the probability on each subsequent flip is 1/2, since they are independent events. The probability of several independent events happening together is the product of their individual probabilities.
The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
you have a 75% chance
Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.
The probability of having a boy or a girl is always 50/50 each time, regardless of previous outcomes. So the theoretical probability of having a girl after having three boys in a row is still 50%.
It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.
To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.
The question is unclear. What do you mean by "almost heads". Please restate the question.
The probability of getting a heads on the first flip is 1/2. Similarly, the probability on each subsequent flip is 1/2, since they are independent events. The probability of several independent events happening together is the product of their individual probabilities.
The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.
The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238
The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)
Oh, what a lovely thought! The probability of giving birth to a girl is 1/2 each time, so the probability of having 5 girls in a row is (1/2) * (1/2) * (1/2) * (1/2) * (1/2) = 1/32. Remember, each birth is a unique and wonderful event, no matter the outcome.
The probability of rolling a 3 with a standard die is 1 in 6. The probability of doing that two times in a row is 1 in 6 squared, or 1 in 36.