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The gender of a child is not random. It is determined by the parents' chromosomes and so the answer depends on whether they have a propensity for male or female offspring. Furthermore, this propensity changes as the parents age. So it is not as simple a question as it might first seem.

However, if you assume that the probability of a girl is 1/2, and remains 1/2, then the answer is (1/2)5 = 1/32 = 3.125%. Of course, many families stop before they reach 5 children!

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Q: What is the probability to giving birth to 5 girls in a row?
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What is the probability of a couple giving birth to five girls in a row?

Probability of girl, assumed to be 0.5. Therefore, probability of 5 girls is 0.5^5 or 0.03125.


What is the probability of having three boys in a row?

This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381


What is the probability of having 3 baby girls in a row?

Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.


What is the probability of twenty-two consecutive same gender births?

Assuming that the chance of a woman giving birth to a boy or a girl is the same (in reality there's about 105 boys born for every 100 girls) then the probability of 22 of the same gender births *in a row* is: P=(0.5)^22=0.0000002384 or 1 in 4,194,304 It depends on the "when" of the question. If you point at a childless woman, and say "She will give birth to 22 children. What is the likelyhood that they will all be girls?" In that case the probability will be one in two-to-the-twenty-second. Pretty long odds. BUT, if you point at a woman with twenty one children, and ask "What are the odds that the next one will be a girl?" Then the answer is one in two. Make sense?


Probability that an event will not occur?

To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.

Related questions

What is the probability of a couple giving birth to five girls in a row?

Probability of girl, assumed to be 0.5. Therefore, probability of 5 girls is 0.5^5 or 0.03125.


What is the probability of a woman giving birth to 6 daughters in a row?

Theoretically we might imagine that the probability that a woman would give birth to a daughter would be 1/2. With this assumption then the probability would be 1/2 x 1/2 x 1/2 x 1/2 x 1/2 x 1/2 = (1/2)6 = 1/26 = 1/64However, there are other considerations:The ratio of boys to girls at birth varies by country. (The most boys to girls occurs in-wait for it-Liechtenstein.) This means that the probability of giving birth to six girls in a row in some country would be less, in others maybe more.If a women gave birth to three girls in a row then you would have some grounds for suspecting that there could be something about her and her partner that favours the conceptions of girls. If this were true then the probability of there being six girls in a row would be much higher.


What is the probability of having three girls in a row?

you have a 75% chance


What is the probability of having three boys in a row?

This question is extremely poorly phrased. The probability of three boys [sitting] in a row at an all boys school is 1. At an all girls school it is 0 and is otherwise somewhere in between. If the question is about birth order, do you take account of the fact that nearly half the families have two or fewer children? So that in half the cases the probability is 0. Finally, children's genders are not independent events. They depend on the parents' ages and their genes. However, if you assume that they are independent events then, given that the probability of a boy is approx 0.52, the probability of giving birth to three boys in a row is 0.523 = 0.1381


What is the probability of having 3 baby girls in a row?

Assuming that the probability of having a baby girl is 1/2 and that of having a baby boy is 1/2, the probability of having 3 baby girls in a row is (1/2)(1/2)(1/2)=1/8.


What is the probability of having 7 girls in a row?

It depends on the context. In a girls' school, it is pretty close to 1 whereas in a boys' school it will be 0.


What is the probability of twenty-two consecutive same gender births?

Assuming that the chance of a woman giving birth to a boy or a girl is the same (in reality there's about 105 boys born for every 100 girls) then the probability of 22 of the same gender births *in a row* is: P=(0.5)^22=0.0000002384 or 1 in 4,194,304 It depends on the "when" of the question. If you point at a childless woman, and say "She will give birth to 22 children. What is the likelyhood that they will all be girls?" In that case the probability will be one in two-to-the-twenty-second. Pretty long odds. BUT, if you point at a woman with twenty one children, and ask "What are the odds that the next one will be a girl?" Then the answer is one in two. Make sense?


What would be the probability that a couple would have 4 sons in succession in a row?

It is not possible to give a proper answer to the question for two main reasons. The first reason is that the probability of boys and girls are not equal. The global probability, at birth is 0.517 for boys and 0.483 for girls. Second, the children's genders are not independent events. Third, the gender ratios change with the parents' (mother's) age. If you choose to ignore all these facts, then the probability is (1/2)4 = 1/16


Probability that an event will not occur?

To find the probability that an event will not occur, you work out the probability that it will occur, and then take this number away from 1. For example, the probability of not rolling two 6s in a row can be worked out the following way:The probability of rolling two 6s in a row is 1/6 x 1/6 = 1/36Thus the probability of not rolling two 6s in a row is 1 - 1/36=35/36.


What is the probability of tossing a dice and getting 3 sixes in a row?

The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.


What is the probability is of getting 3 heads in a row if I toss the coin 10 times?

The probability of getting 3 or more heads in a row, one or more times is 520/1024 = 0.508 Of these, the probability of getting exactly 3 heads in a row, exactly once is 244/1024 = 0.238


A coin is tossed 4 times. What is the probability of getting tails 4 times in a row?

The probability to get tails once is 1/2 (for a fair coin) The probability to get tails twice = the probability to get it once x the probability to get it a second time The probability to get tails 4 times in a row is (1/2)4=1/16 The probability to get tails n times in a row is (1/2)n=1/2n The same thing is also true for heads (same probability: 1/2 each time)