The question is not specific enough for an answer.
If you do not provide the necessary information, asking such a question is pointless.
The answer depends on what the experiment is!
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
To calculate the probability of obtaining one head and two tails when flipping a fair coin three times, we can use the binomial probability formula. The number of ways to arrange one head and two tails is given by the combination formula (C(3, 1) = 3). The probability for each specific arrangement of one head and two tails is ((1/2)^3 = 1/8). Therefore, the total probability is (3 \times (1/8) = 3/8).
The probability of flipping tails in a single coin toss is ( \frac{1}{2} ). To find the probability of flipping tails five times in a row, you multiply the probabilities of each individual toss: ( \left(\frac{1}{2}\right)^5 = \frac{1}{32} ). Therefore, the probability of flipping tails all five times is ( \frac{1}{32} ) or 3.125%.
this isn giong to be my answerP(tails and 5) = 1 P(tails or 1) = 2
this dick
The answer to what I think the question might be, is (1/2)*(1/6) = 1/12
The answer depends on what the experiment is!
The probability to tossing a coin and obtaining tails is 0.5. Rolling a die has nothing to do with this outcome - it is unrelated.
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
It is 0.5
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
It is approx 0.2461
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")
To calculate the probability of obtaining one head and two tails when flipping a fair coin three times, we can use the binomial probability formula. The number of ways to arrange one head and two tails is given by the combination formula (C(3, 1) = 3). The probability for each specific arrangement of one head and two tails is ((1/2)^3 = 1/8). Therefore, the total probability is (3 \times (1/8) = 3/8).