0
The question is not specific enough for an answer.
- Is it one Tails in one toss of a coin or more?
- Is it a five on a roll of a die, a draw from a deck of cards, or a spin of a spinner?
If you do not provide the necessary information, asking such a question is pointless.
Add your answer:
Earn +20 pts
What is the probability of obtaining tails or a three?
The answer depends on what the experiment is!
What is the probability of obtaining tails and a three?
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
What is the probability of obtaining four tails in five flips of a coin?
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
What is the probability of obtaining exactly four tails in five flips of a coin if at least three are tails?
We need to determine the separate event. Let A = obtaining four tails in five flips of coin Let B = obtaining at least three tails in five flips of coin Apply Binomial Theorem for this problem, and we have: P(A | B) = P(A ∩ B) / P(B) P(A | B) means the probability of "given event B, or if event B occurs, then event A occurs." P(A ∩ B) means the probability in which both event B and event A occur at a same time. P(B) means the probability of event B occurs. Work out each term... P(B) = (5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0 It's obvious that P(A ∩ B) = (5 choose 4)(½)4(½) since A ∩ B represents events A and B occurring at the same time, so there must be four tails occurring in five flips of coin. Hence, you should get: P(A | B) = P(A ∩ B) / P(B) = ((5 choose 4)(½)4(½))/((5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0)
What is the probability of obtaining tails or a six?
The answer depends on the experiment: how many coins are tossed, how often, how many dice are rolled, how often.
What is the probability of obtaining tails or a five (Enter the probability as a fraction.)?
this isn giong to be my answerP(tails and 5) = 1 P(tails or 1) = 2
What is the probability of obtaining tails and a six?
this dick
What is the probability Of obtaining tails and five?
The answer to what I think the question might be, is (1/2)*(1/6) = 1/12
What is the probability of obtaining tails or a three?
The answer depends on what the experiment is!
Suppose that you toss a coin and roll and die What is the probability of obtaining tails?
The probability to tossing a coin and obtaining tails is 0.5. Rolling a die has nothing to do with this outcome - it is unrelated.
What is the probability of obtaining exactly four tails in five flips?
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
What is the probability of obtaining two tails or more if three coins are flipped?
It is 0.5
What is the probability of obtaining tails and a three?
Assume the given event depicts flipping a fair coin and rolling a fair die. The probability of obtaining a tail is ½, and the probability of obtaining a 3 in a die is 1/6. Then, the probability of encountering these events is (½)(1/6) = 1/12.
What is the probability of obtaining exactly 4 tails from the 9 flips of the coin?
It is approx 0.2461
What is the probability of obtaining four tails in five flips of a coin?
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
What is the probability of getting five tails in a row?
The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")
What is the probability of obtaining exactly four tails in five flips of a coin if at least three are tails?
We need to determine the separate event. Let A = obtaining four tails in five flips of coin Let B = obtaining at least three tails in five flips of coin Apply Binomial Theorem for this problem, and we have: P(A | B) = P(A ∩ B) / P(B) P(A | B) means the probability of "given event B, or if event B occurs, then event A occurs." P(A ∩ B) means the probability in which both event B and event A occur at a same time. P(B) means the probability of event B occurs. Work out each term... P(B) = (5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0 It's obvious that P(A ∩ B) = (5 choose 4)(½)4(½) since A ∩ B represents events A and B occurring at the same time, so there must be four tails occurring in five flips of coin. Hence, you should get: P(A | B) = P(A ∩ B) / P(B) = ((5 choose 4)(½)4(½))/((5 choose 3)(½)³(½)² + (5 choose 4)(½)4(½) + (5 choose 5)(½)5(½)0)
