The answer to what I think the question might be, is (1/2)*(1/6) = 1/12
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The probability to tossing a coin and obtaining tails is 0.5. Rolling a die has nothing to do with this outcome - it is unrelated.
Assume the coin is fair, so there are equal amount of probabilities for the choices.There are two possible choices for a flip of a fair coin - either a head or a tail. The probability of getting a head is ½. Similarly, the probability of getting a tail is ½.Use Binomial to work out this problem. You should get:(5 choose 4)(½)4(½).(5 choose 4) indicates the total number of ways to obtain 4 tails in 5 flips.(½)4 indicates the probability of obtaining 4 tails.(½) indicates the probability of obtaining the remaining number of head.Therefore, the probability is 5/32.
It is approx 0.2461
The probability of getting five tails in a row is 1/2^5, or 1 in 32.The probability of getting five heads in a row is 1/2^5, or 1 in 32.Thus, the probability of getting either five heads or five tails in five tosses is 1 in 16.(The caret symbol means "to the power of," as in 2^5 means "2 to the 5th power.")
The probability of obtaining 4 tails when a coin is flipped 4 times is: P(4T) = (1/2)4 = 1/16 = 0.0625 Then, the probability of obtaining at least 1 head when a coin is flipped 4 times is: P(at least 1 head) = 1 - 1/16 = 15/16 = 0.9375