The probability is 11/21.
There are 20 numbers in total from 1 to 20. The even numbers in this range are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20, totaling 10 even numbers. Therefore, the probability of picking an even number is the number of even numbers divided by the total numbers, which is ( \frac{10}{20} = \frac{1}{2} ). Thus, the probability of selecting an even number is 0.5 or 50%.
The probability, in a single random selection, is 1/20 or 0.05
A 1 out of 5 chance, or 20%
20 out of 52.
If one card is picked at random from a normal deck of cards, the probability is 20/52 or 5/13.
The probability of picking a distinct set of 3 numbers from 20 is1/[20!/(3!)(17!)]= 1/1140The probability of only picking 3 from 20 is1/20
The probability is 8/20.
There are 20 numbers in total from 1 to 20. The even numbers in this range are 2, 4, 6, 8, 10, 12, 14, 16, 18, and 20, totaling 10 even numbers. Therefore, the probability of picking an even number is the number of even numbers divided by the total numbers, which is ( \frac{10}{20} = \frac{1}{2} ). Thus, the probability of selecting an even number is 0.5 or 50%.
The probability, in a single random selection, is 1/20 or 0.05
A 1 out of 5 chance, or 20%
Since there are 10 odd numbers (1, 3, 5, 7, 9, 11, 13, 15, 17, 19) in the 20 numbers (1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20), the probability of picking an odd number in a random sample is 10 in 20, or 1 in 2, or 0.5.
The probability of picking a 15 or a 16 from the random set [1-20] is 2 in 20, or 1 in 10, or 0.1.
The probability is 1 over 20.
21
There are 8 out of 20 numbers that are prime, so 8/20, or 2/5.
1/400
20 out of 52.