The probability is 8/20.
Although there are infinitely many primes, they become rarer and rarer so that as the number of numbers increases, the probability that picking one of them at random is a prime number tends to zero*. In the first 10 numbers there are 4 primes, so the probability of picking one is 4/10 = 2/5 = 0.4 In the first 100 numbers there are 26 primes, so the probability of picking one is 25/100 = 1/4 = 0.25 In the first 1,000 numbers there are 169 primes, so the probability of picking one is 168/1000 = 0.168 In the first 10,000 numbers there are 1,229 primes, so the probability of picking one is 0.1229 In the first 100,000 numbers there are 9592 primes, so the probability of picking one is 0.09592 In the first 1,000,000 numbers there are 78,498 primes, so the probability of picking one is 0.078498 In the first 10,000,000 numbers there are 664,579 primes, so the probability of picking one is 0.0664579 * Given any small value ε less than 1 and greater than 0, it is possible to find a number n such that the probability of picking a prime at random from the numbers 1-n is less than the given small value ε.
It is 1/13,983,816.
I need to calculate the probability of winning the Mega Million jackpot. First you must choose the correct 5 numbers between 1 and 56. I believe that solution is 56!/51! 5! or The probability of 1/3,819,816 The next step is, in a separate single drawing, choose the correct number between 1-46. So there is a 1/46 chance of picking that number. is the probability of choosing all numbers 1/3,819,816 x 1/46?
1
If two people pick a number from 1 to 80, then there are 79 possible adjacent pairs that these numbers could go in. For each of these pairs, there are two options (one with person a picking the lower number and one with person b picking the lower number). Thus there are 158 possible pairs. The chance that person 1 will pick any given number is 1/80. The chance that person two will pick any given number is 1/80. Thus the probability that they have picked adjacent number is (1/80)2x158 = 0.0246875
The probability is 1/b.
no.
The answer depends on whether the first number is replaced before picking the second. If not, the probability is 0.029
Although there are infinitely many primes, they become rarer and rarer so that as the number of numbers increases, the probability that picking one of them at random is a prime number tends to zero*. In the first 10 numbers there are 4 primes, so the probability of picking one is 4/10 = 2/5 = 0.4 In the first 100 numbers there are 26 primes, so the probability of picking one is 25/100 = 1/4 = 0.25 In the first 1,000 numbers there are 169 primes, so the probability of picking one is 168/1000 = 0.168 In the first 10,000 numbers there are 1,229 primes, so the probability of picking one is 0.1229 In the first 100,000 numbers there are 9592 primes, so the probability of picking one is 0.09592 In the first 1,000,000 numbers there are 78,498 primes, so the probability of picking one is 0.078498 In the first 10,000,000 numbers there are 664,579 primes, so the probability of picking one is 0.0664579 * Given any small value ε less than 1 and greater than 0, it is possible to find a number n such that the probability of picking a prime at random from the numbers 1-n is less than the given small value ε.
The chances of picking a number between 2 to 5 is 4/10 if the numbers to be picked from are 1-10. However, if the numbers to be picked from are 1-100, then the probability drops to 4/100.
The probability, in a single random selection, is 1/20 or 0.05
no. because there are more composite numbers than prime numbers It depends on the place you choose to pick the prime number (e.g. 457 or 7577?). The bigger the number the less likely it is a prime.A formula gives the probability for a number being prime (Prime Number Theorem).
2 numbers. few probabilities. Lets see. Number 1 probability: if your given numbers are this for example, 2 and 7. What is the probability of picking out 7? the Numerator is how many of that number is in the group. They are asking for 7? so how many 7's are in the group? 1. Then the denominator is how many numbers are in the group. There are 2 numbers in the group. so the probability of picking out a 7 would be 1/2. get it? if there were two 7's, then the probability would be 2/2 or 1. I hope I helped.
It is 1/13,983,816.
From 75 to 100 (inclusive), there are 26 numbers, and 13 of them are odd.The probability of picking an odd number is 13/26 = 50%.
The number of combinations of 50 things taken 5 at a time is (50! - 45!) / 5! or 2,118,760, so the probability of winning the lottery on 1 ticket by picking 5 numbers out of 50 numbers is 1 in 2,118,760, or 0.00000047197. More formally, the number of combinations of N things taken P at a time is (N! - (N-P)!) / P!
I need to calculate the probability of winning the Mega Million jackpot. First you must choose the correct 5 numbers between 1 and 56. I believe that solution is 56!/51! 5! or The probability of 1/3,819,816 The next step is, in a separate single drawing, choose the correct number between 1-46. So there is a 1/46 chance of picking that number. is the probability of choosing all numbers 1/3,819,816 x 1/46?