4/54 or 2/27or 1/13.5
The answer depends on how many cards are picked and whether or not the cards are replaced before picking the next one. If only three cards are picked and they are not replaced, the probability is 3*2*1/(52*51*50) = 1/22100 = 0.000 045 2 If the cards are replace, the probability is 3*2*1/523 = 0.000 042 7
One out of three
It is 0.077, approx.
The answer depends on the numbers on the cards in the bag!
The probability of drawing the first face card is 12 in 52. The probability of drawing the second is 11 in 51. The probability of drawing the third is 10 in 50. Thus, the probability of drawing three face cards is (12 in 52) times (11 in 51) times (10 in 50) or (1320 in 132600) or about 0.009955.
4/52
One quarter of the pack are CLUB cards. Three quarters of the pack are NOT CLUB cards. So the chance (probability) of picking a CLUB card is 1 out of 4 = 0.25 The chance (probability) of picking a NOT CLUB card is 3 out of 4 = 0.75 Adding the various probabilities the answer must always be 1.0, which is true here. If the probability of something happening is 1.0, that means the probability is "certainty". It is bound to happen.
The answer depends on how many cards are picked and whether or not the cards are replaced before picking the next one. If only three cards are picked and they are not replaced, the probability is 3*2*1/(52*51*50) = 1/22100 = 0.000 045 2 If the cards are replace, the probability is 3*2*1/523 = 0.000 042 7
To determine the probability of picking 3 cards of one suit and 1 card of another in a standard 52 card deck, consider each card one at a time. The probability of picking a card in any suit is 52 in 52, or 1. Since there are now only 12 cards in the first suit, the probability of picking a card in the same suit is 12 in 51, or 4 in 17, or 0.2353. Since there are now only 11 cards in the first suit, the probability of picking a card in the same suit is 11 in 50, or 0.22. Since there are still 39 cards in the remaining three suits, the probability of picking a card in a suit different than the first is 39 in 49, or 0.7959. The probability of picking 3 cards of one suit and 1 card of another in a standard 52 card deck is, therefore, the product of the probabilities of each card, or (52 in 52) (12 in 51) (11 in 50) (39 in 49), or 267696 in 6497400, or 0.0412, or about 1 in 25.
Red cards will be a 1/3 chance to pick out of three cards .
One out of three
The probability of getting two pairs in a standard deck of playing cards is higher than the probability of getting three of a kind.
The probability of drawing three black cards from a standard pack depends on:whether the cards are drawn at random,whether or not the drawn cards are replaced before the next card is drawn,whether the probability that is required is that three black cards are drawn after however many draws, or that three black cards are drawn in a sequence at some stage - but not necessarily the first three, or that the first three cards cards that are drawn are black.There is no information on any of these and so it is not possible to be certain about the answer.The probability of drawing three black cards, in three random draws - without replacement - from a standard deck, is 0.1176 approx.
It is 0.077, approx.
It is a certainty if you pick 5 cards.
The probability of drawing two blue cards froma box with 3 blue cards and 3 white cards, with replacement, is 1 in 4, or 0.25.The probability of drawing one blue card is 0.5, so the probability of drawing two is 0.5 squared, or 0.25.
The probability of drawing three black cards one at a time with replacement from a standard deck of 52 cards is 1/3x1/2x26/52, which is 0.833.