First of all, there are 12 possible outcomes in total. So that becomes the denominator. There is obviously only one six on a die (dice) and you roll it twice, which means 2. That is how many times you can get 6 in a row (numerator). If you put both numbers together you get a fraction of 2/6, (in lowest terms it is 1/3), in a decimal it is 0.33..., in a percent it is 33%, in a ratio it is 1:3. I hope that helps, good luck on your math problems! (I think)
=)
The probability of rolling doubles with 2 dice is 1 in 6, or about 0.1667. The probability of doing that 100 times in a row is 0.1667100 or about 1.531x10-78.
3/18
The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.
the chance of getting a six is 5 in 36 so five times in a row is 5/36 tot he 5th power = 1 chance in19,349 tries
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
The probability of rolling doubles with 2 dice is 1 in 6, or about 0.1667. The probability of doing that 100 times in a row is 0.1667100 or about 1.531x10-78.
The probability of rolling 6 dice and getting 1 2 3 4 5 and 6 all in a row is one in 720, because you are talking about the permutations of six things taken six at a time, which is 6 factorial.
The probability of rolling 7 once with two dice is 1 in 6, o 0.1667. The probability, then, of doing that twice in a row is 1 in 36, or 0.02778.
the chances of rolling doubles once is 1 in 6; 3 times in a row it is 1 in 216. It does not make any difference after how many times you rolled the dice before.
3/18
(1/6)(1/6)=
The probability of tossing a die and getting three 6's in a row is (1/6)3, or about 0.004630.
the chance of getting a six is 5 in 36 so five times in a row is 5/36 tot he 5th power = 1 chance in19,349 tries
The answer depends on how many times in total the dice are rolled. As the total number of rolls increases, the probability rolling a 6 and 4 three times in a row increases towards 1.
1 in 36
There is insufficient information in the question to answer it. You did not specify how many dice were involved. Please restate the question. In the meantime, I will give a generalized answer. If the probability of rolling a straight is n, then the probability of rolling straight three times in a row is n3. For instance, with three dice, the probability of rolling a straight is 1 in 36, neglecting (i.e. allowing for) wrap-around straights, and ignoring (sorry, but the math is too complex and does not serve the answer anyway) the fact that straights can go in either direction. That 1 in 36 is n=0.02778. The probability of doing that 3 times in a row, then, is 0.00002143.
Assuming that the die is a "normal" one (it has the numbers 1 to 6 and that it is fair), then the probability of rolling six three times in a row is 1/6*1/6*1/6 = 1/216 = 0.00463 The probability of rolling six three times in a row eventually is 1 (ie a certainty).