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What is the probability of rolling 2 number cubes and having the first land on an odd number and the second land on 1'?
(1/2) * (1/6) = 1/12
What is the probability of rolling an even number on a die and rolling an odd number on a second roll of the same die?
0.25 ( P = 0.5 each time)
What is the probability of rolling a 6 the first time and a 1 the second time?
What is the probability of rolling a 6 the first time and a 1 the second time
Rolling three dice what is the probability of rolling an odd number?
The probability that, when rolling three dice none will come up odd is broken down by the probability that on odd roll will occur as an independent event. Rolling the first die has a probability of 3/6 that it will be odd. Rolling the second has the probability of 3/6 that it will be odd. Rolling the third has a probability of 3/6 will be odd. Rolling three and coming up with odd is really the probability that no odd numbers occurred, so therefore an even number DID happen (3/6), and an even number DID happen (3/6), and an even number DID happen (3/6). That's really just 1 - (3/6^3) or simplified 1 - (1/2^3). So therefore the probability that an odd number occurred in 3 die rolls is about 87.5%.
What is the probability of rolling a prime number and the probability of rolling a number greater than 1 on two rolls fo a die?
First you need to work out the probability of rolling a prime number. The prime numbers on a die are 2, 3 and 5. Thus the probability of rolling a prime number is 3/6 which can be simplified to 1/2. The probability of rolling a number greater than 1 is 5/6. The probability of rolling one on one dice and one on the other is therefore 1/2 x 5/6 = 5/12. There are two possible ways round these options could come though. You might get the number greater than one on the first roll, and the prime on the second. Thus we need to multiply the probability by 2, which gives us the final answer of 5/6.
What is the probability of rolling 2 number cubes and having the first land on an odd number and the second land on 1'?
(1/2) * (1/6) = 1/12
What is the probability of rolling an even number on a die and rolling an odd number on a second roll of the same die?
0.25 ( P = 0.5 each time)
What is the probability of rolling a 6 the first time and a 1 the second time?
What is the probability of rolling a 6 the first time and a 1 the second time
Find the probability of rolling a 2 on a number cube and then an even number on two consecutive rolls of a number cube?
1/6,3/6 ----------------------------------------------------------------------------------------------------- The probability of rolling a 2 is: P(2) = 1/6 The probability of rolling an even number is: P(even) = 1/2 The result on the second roll is independent of the result in the first roll. The probability of rolling a 2 and then rolling an even number is: P(2,even no.) = (1/6) ∙ (1/2) = 1/12 = 0.08333... ≈ 8.33%
Rolling three dice what is the probability of rolling an odd number?
The probability that, when rolling three dice none will come up odd is broken down by the probability that on odd roll will occur as an independent event. Rolling the first die has a probability of 3/6 that it will be odd. Rolling the second has the probability of 3/6 that it will be odd. Rolling the third has a probability of 3/6 will be odd. Rolling three and coming up with odd is really the probability that no odd numbers occurred, so therefore an even number DID happen (3/6), and an even number DID happen (3/6), and an even number DID happen (3/6). That's really just 1 - (3/6^3) or simplified 1 - (1/2^3). So therefore the probability that an odd number occurred in 3 die rolls is about 87.5%.
What is the probability of rolling a prime number and the probability of rolling a number greater than 1 on two rolls fo a die?
First you need to work out the probability of rolling a prime number. The prime numbers on a die are 2, 3 and 5. Thus the probability of rolling a prime number is 3/6 which can be simplified to 1/2. The probability of rolling a number greater than 1 is 5/6. The probability of rolling one on one dice and one on the other is therefore 1/2 x 5/6 = 5/12. There are two possible ways round these options could come though. You might get the number greater than one on the first roll, and the prime on the second. Thus we need to multiply the probability by 2, which gives us the final answer of 5/6.
What is the probability of rolling a prime number first and a composite number second with a fair number cube?
It is 1/2*1/3 = 1/6
What is the probability of rolling a 2 and then a 3 with 6-sised cubes?
The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
What is the probability of rolling a 2 on the first dice and an odd number on the second dice?
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
What is the probability of throwing just one one with two dice?
The probability of throwing just one one with two dice can be calculated by considering the different ways it can occur. There are two ways to get one one: rolling a one on the first die and any number on the second die, or rolling any number on the first die and a one on the second die. There are a total of 36 possible outcomes when rolling two dice, so the probability is 2/36, which simplifies to 1/18.
What is the probability when you roll two dice that you roll an odd number on the first die and a 1 on the second die?
The probability when you roll two dice that you roll an odd number on the first die and a 1 on the second die is 1 in 12. The two die are sequentially unrelated, so you can consider them separately. The probability of rolling an odd number is 3 in 6, or 1 in 2. The probability of rolling a 1 is 1 in 6. Multiply the two probabilities together and you get 3 in 36, or 1 in 12.
What is the probability of rolling a 6 and a 4?
The probability of rolling any specific number will be 1/6, as there are 6 equally likely numbers on a dice. The probability of rolling a 6 then a 4 will thus be 1/6 x 1/6 which gives 1/36. Note, however, that there are two ways the dice can be ordered. The first can be 6 and the second 4, or the other way around. So multiply the above probability by 2 and you get 1/18. Thus the probability of rolling a 6 and a 4 is 1/18
