Q: What is the probability of rolling a 2 on your first roll?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

Probability of rolling a 3 is 2/36 & the probability of rolling a 6 is 5/36; probability of rolling a 3 or 5 is 2/36 + 5/36 = 7/36.

On a single roll is it 2/3.

2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.

The probability of rolling a 3 is 1/6. The probability of rolling a 6 is 1/6. There are two ways to roll a 3 and 6: roll 3 on the first die and 6 on the second or roll 6 on the first and 3 on the second. The probability of the first is 1/6 x 1/6 = 1/36. Likewise the probability of the second is 1/6 x 1/6 = 1/36. Combined you get 1/36 + 1/36 = 2/36 = 1/18

If you roll the die often enough the probability is near enough 1 so as to make no difference. On a single roll, the probability is 1/2.

Related questions

The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.

Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.

2/12 or 1/6

The probability of (1 or 2 or 3) on the first (or any) roll is 1/2 = 50% .The probability of (4 or 5 or 6) on the second (or any) roll is 1/2 = 50% .The probability of exactly that result on two rolls is (1/2 x 1/2)= (50% x 50%) = 1/4 = 25% .

In one roll the probability is 1/36.

1/6,3/6 ----------------------------------------------------------------------------------------------------- The probability of rolling a 2 is: P(2) = 1/6 The probability of rolling an even number is: P(even) = 1/2 The result on the second roll is independent of the result in the first roll. The probability of rolling a 2 and then rolling an even number is: P(2,even no.) = (1/6) ∙ (1/2) = 1/12 = 0.08333... ≈ 8.33%

The probability of rolling a sum of 8 on one roll of a pair of dice is 5/36.The probability of not rolling a sum of 8 on one roll of a pair of dice is 31/36.The probability of rolling a sum of 8 twice on two rolls of a pair of dice is(5/36)(5/36) = (5/36)2 .The probability of rolling first a sum of 8 and then rolling a sum that is not 8 on thesecond roll is (5/36)(31/36).The probability of rolling a sum that is not 8 on the first roll and rolling a sum of 8in the second roll is (31/36)(5/36).So The probability of rolling a sum of 8 at least one of two rolls of a pair of dice is(5/36)2 + (5/36)(31/38) + (31/36)(5/36) = 0.258487654... ≈ 25.8%.

Probability of rolling a 3 is 2/36 & the probability of rolling a 6 is 5/36; probability of rolling a 3 or 5 is 2/36 + 5/36 = 7/36.

On a single roll is it 2/3.

Let say the dice has n sides Let first search for the probability to roll a number less or equal to 2 Probability to roll a 1 = 1/n Probability to roll a 2 = 1/n Probability to roll a 1 OR a 2 = Probability to roll a 1 + Probability to roll a 2 = 1/n + 1/n = 2/n Probability to roll a number greater than 2 = 1 - (Probability to roll a 1 OR a 2) = 1 - 2/n = (n-2)/n If n = 6 then the result is (6-2)/6 = 4/6 = 2/3

2/36 what you rolled the first time has nothing to do with the next roll. It's an independent event.

Assuming that a dice roll is purely random, there is a 1 in 6 probability of landing on any number. Since the second roll depends on the probability of the first, they factor together: First Roll: 1/6 Second Roll: (1/6)(1/6) = 1/36 If you were rolling both dice at once, however, the math would be completely different.