2/12 or 1/6
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
Rolling a sum of 15 on three rolls of a die, when the first roll is a 4, is the same as rolling a sum of 11 on the second and third roll. The probability of rolling 11 on two dice is 3 in 36, or 1 in 12.
If you toss the die often enough then the probability of getting the sequence 2-2-1 is 1: a certainty. The probability of getting the result in the first three tosses is 1/216.
Possible results when rolling the first cube = 6 Possible results when rolling the second cube = 6 Possible results when rolling two cubes = 6 x 6 = 36 How many of these 36 possibilities are snake-eyes ? Only 1 . Probability of snake-eyes on the first roll = 1/36 Probability of snake-eyes on the second roll = 1/36 Probability of snake-eyes on both rolls = 1/36 x 1/36 = 1/1,296 = 0.077 percent Odds = (1 in 1,296) or (1,295 to 1) against it.
The probability of rolling any specific number will be 1/6, as there are 6 equally likely numbers on a dice. The probability of rolling a 6 then a 4 will thus be 1/6 x 1/6 which gives 1/36. Note, however, that there are two ways the dice can be ordered. The first can be 6 and the second 4, or the other way around. So multiply the above probability by 2 and you get 1/18. Thus the probability of rolling a 6 and a 4 is 1/18
What is the probability of rolling a 6 the first time and a 1 the second time
The probability of rolling a 2 on the first roll is 1 in 6. The probability of rolling a 3 on the second roll is 1 in 6. However, the probability of rolling a 2 on the first roll and 3 on the second roll before you roll at all is 1/6 x 1/6 = 1 in 36.
1/6 on the first roll, and 1/6 of rolling a six on the second roll. Overall, the chances of you rolling a 5 on the first and a six on the second is 1/3.
None, because you cannot have the first or second dice: it is the first die or second die. The probability is 1/6 * 1/2 = 1/12
The probability of rolling a 3 on a single die is 1/6. Similarly, the probability of rolling a 5 on a single die is also 1/6. When rolling the die twice, the probabilities are independent events, so you multiply the probabilities together: (1/6) * (1/6) = 1/36. Therefore, the probability of rolling a 3 the first time and a 5 the second time is 1/36.
Assuming you are talking about fair, six-sided dice, then the probability of rolling a 1 on the first roll in 1/6, and the probability of rolling a 2 on the second roll is 1/6. Putting these together, the probability of rolling 1 on the first die and 2 on the second die is 1/36. If you do not care about the order, then you could roll 1,2 or 2,1; in this case the probability would be 2/36, or 1/18.
The probability of rolling a 3 is 1/6. The probability of rolling a 6 is 1/6. There are two ways to roll a 3 and 6: roll 3 on the first die and 6 on the second or roll 6 on the first and 3 on the second. The probability of the first is 1/6 x 1/6 = 1/36. Likewise the probability of the second is 1/6 x 1/6 = 1/36. Combined you get 1/36 + 1/36 = 2/36 = 1/18
The probability is 1 out of 36, or about 3%, I think.
1/6 + 1/6 = 1/3
13/204
Of all the six numbers on a cube, only the '5' is not a factor of 12.Probability of rolling a factor of 12 on the first cube = 5/6 .Probability of rolling a factor of 12 on the second cube = 5/6 .Probability of rolling a factor of 12 on both cubes = (5/6 x 5/6 ) = 25/36 = 694/9 %.
If the first roll is a three, it's impossible to get an eleven (the highest you can get is a 9), so the probability is 0. The way to get a sum of 7 is to add 3 and 4. The probability of getting a 4 on the second die is 1/6. Therefore, by adding the two probabilities of the outcomes (0 and 1/6), you get the answer: 1/6.