depends dude
If using a normal cube, the probability is 0.
The probability, with a standard dart board, is 0.
1/9
1:6
2 sides out of 6 so 1 in 3.
The probability of scoring an exact value for a continuous variable is zero for any value. The probability of scoring 115 (or more) is 15.87%
If using a normal cube, the probability is 0.
The probability, with a standard dart board, is 0.
1/9
1:6
Assuming they are fair dice that are numbered 1 to 6, the probability is 2/36 = 1/18
2 sides out of 6 so 1 in 3.
one in sixsame for any number
it is 1/8
If you throw a fair die one time, the chance of a four is 1/6 or about .1667
The answer depends on how many sides the spinner has and how they are numbered. It also depends on how many time it is spun.
For complex events, it is possible to calculate the probability of events, but often extremely difficult. In the given example, for an "average" person (that would need some definition to start with) you would need to know the probability of them scoring a basket without the blindfold - this can be found by observing a number of "average" people attempting a number of baskets and seeing how many are successful (the greater the number of observations, the better the accuracy of the [estimation of the] probability. Also, the effect of blindfolding them needs to be found - this is not so easy, but some measure could possibly be made - and then combining this effect and the probability found some estimation of the probability of the required event can be calculated. Someone has analysed tennis scoring and given the probability of one of the players winning a point (which can be estimated fairly accurately through past observation) has calculated the probability of them winning the match; however, each match (and even a game within a match) can be affected by further factors (eg one player suffering a small injury) which modify the probability of winning a point, but a calculated probability can still be made.