This is one of those cases where it is probably easier to think what is the probability of not doing it, then subtracting that from 1 to get the probability of doing it. To not get at least one head and one tail, you would have to get all heads or all tails. To get all heads, the probability is (1/2)5. To get all tails is the same probability; so double it to get the probability of either of those. 2(1/2)5=1/16. Subtract the 1/16 from 1 to get 15/16. Answer: 15/16
The probability is 0.998
The probability is 5/16.
The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%
The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.
Since each event is independent, the probability remains at 0.5.
The probability is 0.998
The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%
The probability is 5/16.
The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%
It is 0.3125
The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.
Since each event is independent, the probability remains at 0.5.
It is 60/100 = 0.6
one out of 5 or 2 out of 10
Because a coin is two-sided, 50/50 is always the probability. Unless your coin lands on the grass (on the lawn), then it will probably land on its edge.
It is 1/8 = 0.125
The empirical probability can only be determined by carrying out the experiment a very large number of times. Otherwise it would be the theoretical probability.