This is one of those cases where it is probably easier to think what is the probability of not doing it, then subtracting that from 1 to get the probability of doing it. To not get at least one head and one tail, you would have to get all heads or all tails. To get all heads, the probability is (1/2)5. To get all tails is the same probability; so double it to get the probability of either of those. 2(1/2)5=1/16. Subtract the 1/16 from 1 to get 15/16. Answer: 15/16
The probability is 0.998
The probability is 5/16.
The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%
The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.
Since each event is independent, the probability remains at 0.5.
The probability is 0.998
The probability of tossing a coin 9 times and getting at least one tail is: P(9 times, at least 1 tail) = 1 - P(9 heads) = 1 - (0.50)9 = 0.9980... ≈ 99.8%
The probability is 5/16.
The probability of tossing a coin 5 times and getting all tails is:P(TTTTT) = (1/2)5 = 0.03125 ≈ 3.13%
The probability of getting 3 is virtually 1. It is 1.76 septillionths less than 1.
It is 0.3125
Since each event is independent, the probability remains at 0.5.
It is 60/100 = 0.6
one out of 5 or 2 out of 10
Because a coin is two-sided, 50/50 is always the probability. Unless your coin lands on the grass (on the lawn), then it will probably land on its edge.
It is 1/8 = 0.125
1/2 chance of getting heads or tails 5 times 1/10