The answer depends on the design of the spinner: how many sides and what numbers on them.
If the probability of an event will occur is p, then the probability that it will occur in n trials is pn.(That's p raised to the n power). So if you bet on 12 numbers, then (38-12=26) numbers are empty. The probability of the ball landing on one of these empty numbers is 26/38. So (26/38)^11 = 0.01538, which is about 1.538 % or a 1 in 65 chance.
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
The answer depends on the shape of the spinner and the numbers on it.
The chances of one of these numbers NOT appearing on one spin are 29 out of 37 ie 78.4%, so for 40 spins it is (29/37)^40 which is a remote 0.006%!
The answer depends on the design of the spinner: how many sides and what numbers on them.
roulette
If the probability of an event will occur is p, then the probability that it will occur in n trials is pn.(That's p raised to the n power). So if you bet on 12 numbers, then (38-12=26) numbers are empty. The probability of the ball landing on one of these empty numbers is 26/38. So (26/38)^11 = 0.01538, which is about 1.538 % or a 1 in 65 chance.
roulette
The probability is 0.0198. The probability of that happening twice is 0.000393 Is this the odds of it happening twice with the same number?
Its name says it all. It simply spins and stops at your command.
37 to 1. there are 37 slots on a roulette wheel numbered 0 to 36. if the winning number is 26 and the croupier spins the ball again there are still 37 slots. no slots are removed or added...so 37 to 1...the croupier spins the ball again there are still 37 slots. no slots are removed or added...and so forth
There is no guaranteed strategy for winning at roulette, as it is a game of chance. However, some players use the Martingale system, where they double their bet after a loss in hopes of recouping losses. It's important to remember that the outcome of each spin is independent and cannot be predicted based on previous spins. It's crucial to set a budget and stick to it to avoid losing more than you can afford.
If you mean by the players, no. If you mean by the dealers, yes.
If a five color spinner with equal sections of red blue green yellow and orange is spun six times, the probability of getting no reds in all six spins is 26.2%. The probability of no red on one spin is 4 out of 5, or 0.8 The probability of no red in six spins is 0.86.
That woul mean that the ball landed in one of the remaining 29 slots for 41 and 42 spins. Therefore the answer is 29/37^41 and 29/37^42
The answer depends on the shape of the spinner and the numbers on it.