50 %
The probability that he will not win both games is 0.58
The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
To find the probability that neither of the two cards Mayela picks says WIN, we first note that there are 8 cards in total, with 2 WIN cards and 6 non-WIN cards. The probability that the first card she picks is not a WIN card is 6/8 (or 3/4). After picking one non-WIN card, there are 7 cards left, with 5 of those being non-WIN cards. The probability that the second card is also not a WIN card is 5/7. Thus, the overall probability that neither card says WIN is (6/8) * (5/7) = 30/56, which simplifies to 15/28.
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%
The probability that he will not win both games is 0.58
The odds are 1 in 200. The probability of winning is 0.005.
The total number of alphabets is 26. So the probability of letter C = No of time c is present in the alphabets / Total number of alphabets So probability of letter c is 1/26
You cant win
To determine the probability of the spinner landing on B and then C, we need to know the individual probabilities of landing on B and C. Assuming the spinner is fair and has an equal number of sections for A, B, and C, the probability of landing on B is 1/3, and the probability of landing on C is also 1/3. Thus, the combined probability of landing on B first and then C is (1/3) * (1/3) = 1/9.
The probability is 0.416667 or 41.67%
390
The Probability of NOT reading newspaper a is .8 The Probability of NOT reading Newspaper b is .84 The probability of NOT reading Newspaper c is .86 Therefore, .8*.84*.86=0.57792=57.792%
the probability would be 1/3
with color 1/48870360
probability of undefeated: 0 out of a billion........................... probability of super bowl win: 1 out of a billion.............................
1 in 5