2*(4/52)*(13/52) = 2*(1/13)*(1/4) = 1/26
Abolut 4 in208
2 in 52, or 1 in 26, or about 0.03846.
The probability is 1/2.The probability is 1/2.The probability is 1/2.The probability is 1/2.
The probability of drawing a red card followed by a spade is (1 in 2) times (1 in 4), or 1 in 8, or 0.125. The probability of drawing a spade followed by a red card is (1 in 4) times (1 in 2), or 1 in 8, or 0.125. Since you have two distinct desired outcomes, add them together, giving a probability of drawing a red card and a spade of 0.25.
The answer is 9/149.
65-126
In the first two draws, the probability is 1/15.
The probability of drawing aces on the first three draws is approx 0.0001810
2*(4/52)*(13/52) = 2*(1/13)*(1/4) = 1/26
Abolut 4 in208
It is approx 0.44
The probability is 1/2.The probability is 1/2.The probability is 1/2.The probability is 1/2.
2 in 52, or 1 in 26, or about 0.03846.
4/221
With replacement, the odds of the second extraction do not change after the first, because of independence of the two extractions. Hence, the probability of extracting two reds is (3/5)*(3/5), the probability of two greens is (2/5)*(2/5) and that of one red and one green is 2*(3/5)*(2/5).
Any 2 of 12 is (12 x 11)/2 = 66. Any 2 from 6 is (6 x 5)/2 = 15 so the probability is 15 out of 66 ie 0.227 or 22.7%