2*(4/52)*(13/52) = 2*(1/13)*(1/4) = 1/26
Abolut 4 in208
2 in 52, or 1 in 26, or about 0.03846.
The probability is 1/2.The probability is 1/2.The probability is 1/2.The probability is 1/2.
The probability of drawing a red card followed by a spade is (1 in 2) times (1 in 4), or 1 in 8, or 0.125. The probability of drawing a spade followed by a red card is (1 in 4) times (1 in 2), or 1 in 8, or 0.125. Since you have two distinct desired outcomes, add them together, giving a probability of drawing a red card and a spade of 0.25.
The answer is 9/149.
65-126
In the first two draws, the probability is 1/15.
The probability of drawing aces on the first three draws is approx 0.0001810
2*(4/52)*(13/52) = 2*(1/13)*(1/4) = 1/26
It is approx 0.44
Abolut 4 in208
2 in 52, or 1 in 26, or about 0.03846.
The probability is 1/2.The probability is 1/2.The probability is 1/2.The probability is 1/2.
4/221
Any 2 of 12 is (12 x 11)/2 = 66. Any 2 from 6 is (6 x 5)/2 = 15 so the probability is 15 out of 66 ie 0.227 or 22.7%
With replacement, the odds of the second extraction do not change after the first, because of independence of the two extractions. Hence, the probability of extracting two reds is (3/5)*(3/5), the probability of two greens is (2/5)*(2/5) and that of one red and one green is 2*(3/5)*(2/5).