Assuming the probability of a boy is 0.5, the probability of a boy and boy and boy is 0.5 * 0.5 * 0.5 = 0.125.
The probability is indeterminate. I might ask a student or I might not.
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
The probability of a boy is still 0.5 no matter how many prior children there are.
Probability of picking a student is 800 / (800+50+150) = 800 / 1000 = .8.
Probability that a girl is chosen = 23/45 = .511 So, the probability that a boy is chosen = 1 - .511 = .489
Assuming the probability of a boy is 0.5, the probability of a boy and boy and boy is 0.5 * 0.5 * 0.5 = 0.125.
The probability is indeterminate. I might ask a student or I might not.
If a student is picked at random what is the probability that he/she received an A on his/her fina?
The answer to this is 1 minus the probability that they will have 3 or fewer children. This would happen only if they had a boy as the first, second or third child. The probability they have a boy as first child is 0.5 The probability they have a boy as second is 0.25 The probability they have a boy as third is 0.125 Thus the total probability is 0.875 And so the probability they will have more than three children is 1-0.875 or 0.125
In French, "boy student" is translated as "garçon étudiant."
The probability of a boy is still 0.5 no matter how many prior children there are.
Probability of picking a student is 800 / (800+50+150) = 800 / 1000 = .8.
"Boy student" in English is estudiante in Spanish.
The probability is 0.5
50%
1:1