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What is the probability that at least one coin will be tails?

The answer depends on how many coins were tossed.


What is the probability of flipping 4 coins and getting 3 tails?

If they are fair coins, the probability is 0.25


What is the probability of tossing at least one head with 3 coins?

3 coins can land in 8 different ways. Only one of these ways is all tails. So the probability of rolling at least one heads is 7/8 = 87.5% .


If 4 coins are tossed what is the probability of 4 tails?

The probability is 1/16.


When tossing 5 coins simultaneously can you find the probability that at least 1 head is showing?

Probability not at least 1 head showing is when all 5 coins are tails: (1/2)5=1/32 Therefore probability at least 1 head is showing is 1-1/32=31/32


What is the probability of flipping three tails when three coins are flipped?

The probability of flipping three tails with three coins is (1 in 2)3 or 1 in 8 or 0.125.


What is the probability of getting a least one tail when tossing eight fair coins?

The probability of getting at least 1 tails is (1 - probability of getting all heads) The probability of getting all heads (no tails) is ½ x ½ x ½ x ½ x ½ x ½ x ½ x ½ = 1/256 = 0.00390625 so the probability of getting at least ONE tails is 1-0.30390625 = 0.99609375 = 255/256


What is the probability of flipping 5 coins and getting all tails?

The probability of getting all tails is 1/25 = 1/32


If a coin is tossed then what is the probability that the number is 5?

Coins do not have numbers, there is only the probability of heads or tails.


What is the probability of tossing three coins and having all of them show tails?

When we toss a coin getting head or tail have equal probability of 50% - that is, out of the two possible outcomes getting the specified one becomes 1/2 probability. When we toss three coins, the probability of getting all the coins showing tails is given by (1/2) * (1/2) * (1/2) equal to 1/8 or 12.5 % chance. Alikban


If you toss 4 coins what is the chance of them all landing on tails?

The probability of a fair coin landing on tails is 0.5. The probability of 4 tails is .5*5*.5*.5 = 0.0625.


When tossing 5 coins simultaneously find the probability that at least 1 head is showing.?

This is easiest to solve by working out the probability that no heads show and subtracting this from 1 to give the probability that at least one head shows: Assuming unbiased coins which won't land and stay on their edge, the probability of head = probability of tail = ½ → probability no heads = probability 5 tails = ½^5 = 1/32 → probability of at least one head = 1 - 1/32 = 31/32 = 0.96875 = 96.875 % = 96 7/8 %