Assuming fair dice: With 3 dice there are 6 x 6 = 36 possible permutations (the two dice can be identified and are independent of each other). Of these there are 3 ways (1+3, 2+2, 3+1) of getting four. Probability of getting a four with 2 dice on one roll = 4/36 = 1/9 As rolls are independent, the probability of getting 4 with 2 dice 3 times in a row is 1/9 x 1/9 x 1/9 = 1/729 So the odds of it are 728 to 1 against, ie 1 in 729 or about 0.14 %.
There are 9 odd sums that you can get from rolling two dice.
The probability of rolling a 9 with two dice is 4/36 or 1/9. There are 36 possible combinations and a 9 is obtained by rolls of 3,6; 4,5; 6,3; & 5,4.
There 36 possibilities, and out of the 36, there are 26 possibilities of getting a sum less than 9. 26/36 = 2/3
The chance is 9%
There are 36 permutations of two dice. Of these, 9 have a sum of 5 or 6, so the probability of rolling a sum of 5 or 6 on two dice is 9 in 36, or 1 in 9, or about 0.1111.
There are 36 permutations of two dice.1 Of these 4 have a sum of 9, specifically 36, 45, 54, and 63. Therefore, the probability of throwing a sum of 9 on two dice is 4 in 36, or 1 in 9, or about 0.1111. ---------------------------------------------------------------------------------- 1It does not matter it you throw one die two times or two dice once. Since these are independent events, the probabilities are the same either way.
P(9) ≈ 11.11%When two dice are rolled there are 36 equiprobable events.The number of events that produce a sum of 9 are 4: (6,3), (5,4), (4,5) and (3,6).So the probability of getting a sum of 9 is, P(9) = 4/36 = 1/9 = 0.1111.... ≈ 0.1111≈ 11.11%
I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.I suppose you mean, at least one of those numbers. Just calculate the probability of NOT getting any of those, and take the complement. The probability of not getting a one nor a five on a single die is 4/6 or 2/3. For two dice, the probability is 2/3 x 2/3 = 4/9. So, the probability of getting at least a one or a five with two dice is 1 - 4/9 = 5/9.
Assuming fair dice: With 3 dice there are 6 x 6 = 36 possible permutations (the two dice can be identified and are independent of each other). Of these there are 3 ways (1+3, 2+2, 3+1) of getting four. Probability of getting a four with 2 dice on one roll = 4/36 = 1/9 As rolls are independent, the probability of getting 4 with 2 dice 3 times in a row is 1/9 x 1/9 x 1/9 = 1/729 So the odds of it are 728 to 1 against, ie 1 in 729 or about 0.14 %.
There is 4 ways to roll a 9 with 2 dice, and 36 possible outcomes. So, the probability of rolling a sum of 9 with two dice is 4/36 or 1/9.
There are 9 odd sums that you can get from rolling two dice.
The probability of rolling a 9 with two dice is 4/36 or 1/9. There are 36 possible combinations and a 9 is obtained by rolls of 3,6; 4,5; 6,3; & 5,4.
5 out of 12
There 36 possibilities, and out of the 36, there are 26 possibilities of getting a sum less than 9. 26/36 = 2/3
The chance is 9%
1/9