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Q: What is the product 6 5i?
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Related questions

What is the complex conjugate -6-5i?

6+5i


2 plus 5i plus 6 plus 3i?

I assume that "I" is a variable2+5i+6+3i7i+6+3i10i+616i is the answer


What is the magnitude of -1 - 5i?

-6


What is the reciprocal of 3 plus 5i?

1/(3+5i)=(3-5i)/((3+5i)(3-5i))=(3-5i)/(9+25)=(3-5i)/34


Complex conjugate of 5i?

0 + 5i Its complex conjugate is 0 - 5i


What is 1 divided by 2 plus 5i in the form a plus bi?

1/(2 + 5i) (multiply both the numerator and the denominator by 2 - 5i)= 1(2 - 5i)/(2 + 5i)(2 - 5i)= (2 - 5i)/(4 - 25i2) (substitute -1 for i2)= (2 - 5i)/(4 + 25)= (2 - 5i)/29= 2/29 - (5/29)i


What is the conjugate of 7-5i?

12


What is the conjugate of 11 plus 5i?

To find the complex conjugate change the sign of the imaginary part: For 11 + 5i the complex conjugate is 11 - 5i.


How do you solve 2 divided by 5i?

0.4


How do you find the additive inverse of a complex number?

You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).You take the additive invers of the real and of the imaginary part. For instance, the additive inverse of: (3 - 5i) is (-3 + 5i).


P and q are complex number's where p equals 2 plus 5i and q equals 6 minus i - find pq?

p = (2 + 5i)q = (6 - i)pq = (2 + 5i) (6 - i)pq = 12 + 30i - 2i - 5i2pq = 12 + 28i + 5pq = 17 + 28iIts the same as multiplying polynomials. Just multiply all the combinations of terms, group, and simplify.


What is conjugate of 2 3i 2-5i?

The conjugate of 2 + 3i is 2 - 3i, and the conjugate of 2 - 5i is 2 + 5i.