Any number multiplied by zero is zero. (10b also means 10 times zero.)
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
x - 6x = 0-5x= 0x = 0/-5which equals x = 0
First, factorise: x2 + 5x - 6 = (x + 6)(x - 1) = 0; whence, either x + 6 = 0, or x - 1 = 0. The product of two factors equals zero, exactly when one or other of the two factors equals zero. Thus, the solution must be x = 1 or -6. If x equals either of those two values, then the original equation will be true.
Simply put, No.
The roots are: x = 1 and x = 7 So: 7*1 = 7
8
Suppose x3-4x = 0. To solve, factor: x3-4x = x(x2-4) = x(x+2)(x-2) = 0 Now, a product equals 0 if and only one or more of the factors equals 0, so set each factor to 0 and solve. The roots are 0,-2 and +2.
The product of the roots of the equation 2x2 -x -2 = 2 is 2x2 -x -2 = 2.
3 x - 7 = -21
x=0
"xy" refers to the product of "x" and "y". Just substitute the variables for numbers, and do the multiplication.
x - 6x = 0-5x= 0x = 0/-5which equals x = 0
First, factorise: x2 + 5x - 6 = (x + 6)(x - 1) = 0; whence, either x + 6 = 0, or x - 1 = 0. The product of two factors equals zero, exactly when one or other of the two factors equals zero. Thus, the solution must be x = 1 or -6. If x equals either of those two values, then the original equation will be true.
Simply put, No.
It equals 0
x=0
If you are solving for x, x2 - 2x + 1 = 0 Factor: (x-1)(x-1) = 0 Therefore: (x - 1)2 = 0 (x - 1) = 0 x = 1