56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
Product of the two prime numbers is the LCM. For example 3, 7 have 21 as LCM
As for example 98 as a product of its prime factors is: 2*7*7 = 98
2 x 3 x 5 x 7 = 210
The first four prime numbers are 2, 3, 5, 7. The product of these numbers is 2 x 3 x 5 x 7 = 210
The first four prime numbers are 2, 3, 5, and 7. The product of these numbers is 210.
The first five prime numbers are 2, 3, 5, 7, 11. The product of these five numbers is equal to 2 x 3 x 5 x 7 x 11 = 2310.
2*3*5*7*11, or the product of the first 5 prime numbers
28 is the product of the prime numbers 2 x 2 x 7.
The first prime numbers are 2, 3, 5, 7, 11. When multiplied together the product is 2310. It is the smallest number that has the first five numbers as its factors.
Well, darling, the first prime number is 2 and the fifth prime number is 11. Multiply those bad boys together and you get 22. So, the product of the first prime number and the fifth prime number is 22. Math doesn't have to be boring, honey!
It is: 2*3*5*7 = 210
3 and 7 are prime numbers whose product is 21.
56 = 7 x 8 = 7 x 23 then 56 is not a product of 3different prime numbers
It is 2 and as a product of its prime numbers in exponents 2^7 = 128
70 written as a product of prime numbers: 2 x 5 x 7