y x 8
(y^2)x8
5y-8 = 16 5y = 16+8 5y = 24 y = 24/5 = 4.8
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
5+(8*X) = Y You don't have enough info. to solve for Y.... I think. :)
y x 8
abs(y^3 - 4) < 8*y
As an expression it is: 8z+6.5y
If you mean: 3y = 24 then y is 8 and 8+8.6 = 16.8
(y^2)x8
5y-8 = 16 5y = 16+8 5y = 24 y = 24/5 = 4.8
To write this algebraically: 7(y^3)|y = 2 Substitute 2 for y: 7(2^3) 2^3 = 8, so substitute 8 for (2^3): 7*8 = 56
x and y are variables, so unless you define their values, this question has no definite answer. but, i can simplify it for you: xy-8, x*y-8, (xy)-8, xy+-8. There are a lot more ways, but i recommend you use XY-8.
The expression "8 less than the product of y and 9" can be represented as 9y - 8. This is because you first multiply y by 9 to get the product of y and 9, and then subtract 8 from that product. So, 9y - 8 is the algebraic expression for "8 less than the product of y and 9."
5+(8*X) = Y You don't have enough info. to solve for Y.... I think. :)
7 and 8Since:x+y=15 or x=15-yxy=56so that y(15-y)=5615y-y2=56y2-15y+56=0(y-7)(y-8)=0which makes y=8 or y=7
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