0
36
Brielle Cruickshank
Wiki User
∙ 14y ago8 and -4
8 + (-4) = 4
8 * (-4) = -32
Add your answer:
Earn +20 pts
What is the sum of seven and the product of x and y?
7+xy
The sum of two numbers is 10 and their product is 20 find the sum of the reciprocal of the number?
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
Robert's numbers is between 20 and 32 the sum of the digits is 10 what is the number how do i solve it?
Suppose the number, when written is XY. Then sum of digits = 10 implies that X+Y = 10 Also, 20 < XY < 32 implies that X = 2 or 3. Suppose X = 3 Then X+Y = 10 requires Y = 7. But that is not possible because the number cannot be greater than 32. So, X must be 2. And then, X+Y = 10 implies that Y = 8 and so the number is 28.
X plus XY equals 8 solve for Y?
x+xy=8 xy=-x+8 y=-1+8/x
How xy plus x plus y plus 1 will solve?
xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.
The sum of x and y decreased by their product?
The sum of x and y decreased by their product is (x + y)- xy.
What is the sum of seven and the product of x and y?
7+xy
Which expression can be best described as a sum divided by a product?
(a + b)/(xy)
The sum of two number is 10 and their product is 30 the sum of their reciprocals is?
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
If the sum of two numbers is 7 and there product is 25 what is the sum of there reciprocals?
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
Find the sum of the reciprocals of two real numbers given that these numbers have a sum of 150 and a product of 40?
1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75
The sum of two numbers is 10 and their product is 20 find the sum of the reciprocal of the number?
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
If the sum of two numbers is 12 and the product is 24 What is the sum of the reciprocals?
1/x+1/y y/xy+x/xy x+y/xy=12/24 12/24=1/2 1/2 is the answer.
The sum of xy times 3?
The sum of xy times 3 is equal to 3(xy).
The sum of two numbers is 10 and their product is 20 find the sum of the reciprocal of the number.?
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
Robert's numbers is between 20 and 32 the sum of the digits is 10 what is the number how do i solve it?
Suppose the number, when written is XY. Then sum of digits = 10 implies that X+Y = 10 Also, 20 < XY < 32 implies that X = 2 or 3. Suppose X = 3 Then X+Y = 10 requires Y = 7. But that is not possible because the number cannot be greater than 32. So, X must be 2. And then, X+Y = 10 implies that Y = 8 and so the number is 28.
What two numbers have a product of 24 and a sum of 23?
xy=24 and y=23-x so x(23-x)=24, which is x2-23x+24 = 0, and you solve this using the formula method to get approximately 21.95 and 1.05 If the product had been 23 and the sum 24 the equation would have factorized easily and you would have 1 and 23
