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8 and -4

8 + (-4) = 4

8 * (-4) = -32

Q: Solve the sum of x and y is 4 and the product xy is -32?

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7+xy

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

Suppose the number, when written is XY. Then sum of digits = 10 implies that X+Y = 10 Also, 20 < XY < 32 implies that X = 2 or 3. Suppose X = 3 Then X+Y = 10 requires Y = 7. But that is not possible because the number cannot be greater than 32. So, X must be 2. And then, X+Y = 10 implies that Y = 8 and so the number is 28.

x+xy=8 xy=-x+8 y=-1+8/x

xy + x + y + 1 is an expression, not an equation. An expression cannot be solved.

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The sum of x and y decreased by their product is (x + y)- xy.

7+xy

(a + b)/(xy)

Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3

Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25

1/x + 1/y = (y+x)/xy But y + x = sum = 150, and xy = product = 40 So sum of reciprocals = 150/40 = 3.75

Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2

1/x+1/y y/xy+x/xy x+y/xy=12/24 12/24=1/2 1/2 is the answer.

The sum of xy times 3 is equal to 3(xy).

1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.

Suppose the number, when written is XY. Then sum of digits = 10 implies that X+Y = 10 Also, 20 < XY < 32 implies that X = 2 or 3. Suppose X = 3 Then X+Y = 10 requires Y = 7. But that is not possible because the number cannot be greater than 32. So, X must be 2. And then, X+Y = 10 implies that Y = 8 and so the number is 28.

xy=24 and y=23-x so x(23-x)=24, which is x2-23x+24 = 0, and you solve this using the formula method to get approximately 21.95 and 1.05 If the product had been 23 and the sum 24 the equation would have factorized easily and you would have 1 and 23