You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore,
x2 + 13x + 40 = (x + 8) (x + 5)
that would be 8 and 5
If you want to use the quadratic equation to solve it instead of factoring, the equation is x = (-b + or - the square root of (b2- 4ac))/2a
a in this case is 1, b is 13, and c is 40
So, plug a, b, and c into the above equation and do it once with adding and once with subtracting. There will be two x values given if you do it both times, 8 and 5.
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
Assume this quadratic equation equals zero. Then :-x2 - 13x + 40 = 0, this can be factored (x - 8)(x - 5) = 0This holds true when either x - 8 = 0 or x - 5 = 0When x - 8 = 0 then x = 8 : When x - 5 = 0 then x = 5
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
Divide all terms by their GCF which is 20 and so w^2+5w+2 which when factored is (m+4.5616)(m+0.4384) to four decimal places A more accurate answer can be found by using the quadratic equation formula
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals". There is no symbol before 13x.
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
Assume this quadratic equation equals zero. Then :-x2 - 13x + 40 = 0, this can be factored (x - 8)(x - 5) = 0This holds true when either x - 8 = 0 or x - 5 = 0When x - 8 = 0 then x = 8 : When x - 5 = 0 then x = 5
56
This doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-17 plus or minus the square root of -671) divided by 12x = -1.4166 + 2.158638974498103ix = -1.4166 - 2.158638974498103iwhere i is the square root of negative one.
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
Divide all terms by their GCF which is 20 and so w^2+5w+2 which when factored is (m+4.5616)(m+0.4384) to four decimal places A more accurate answer can be found by using the quadratic equation formula
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "equals". There is no symbol before 13x.
The result of the equation - 130 plus 80 plus 60 plus 40, is found as follows;130 + 80 + 60 + 40= ( 130 + 80 ) + 60 + 40= 210 + ( 60 + 40 )= 210 + 100= 310Answer = 310
The result of the equation - 130 plus 80 plus 40 plus 80, is found as follows;130 + 80 + 40 + 80= ( 130 + 80 ) + 40 + 80= 210 + ( 40 + 80 )= 210 + 120= 330Answer = 330
It is an equation in one variable.
20
Rearrange the second equation as x = 10+y and then substitute it into the first equation which will create a quadratic equation in the form of: 2y2+30y+100 = 0 and when solved y = -10 or y = -5 Therefore the solutions are: x = 0, y = -10 and x = 5, y = -5