You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore,
x2 + 13x + 40 = (x + 8) (x + 5)
that would be 8 and 5
If you want to use the quadratic equation to solve it instead of factoring, the equation is x = (-b + or - the square root of (b2- 4ac))/2a
a in this case is 1, b is 13, and c is 40
So, plug a, b, and c into the above equation and do it once with adding and once with subtracting. There will be two x values given if you do it both times, 8 and 5.
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A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
Assume this quadratic equation equals zero. Then :-x2 - 13x + 40 = 0, this can be factored (x - 8)(x - 5) = 0This holds true when either x - 8 = 0 or x - 5 = 0When x - 8 = 0 then x = 8 : When x - 5 = 0 then x = 5
The solution to this equation is that h is equal to -4. You can substitute this value for h into the equation to get -4 x -9 - 6 plus 12 x -4 plus 40 equals 22, or 36 - 6 plus - 48 plus 40 equals 22.
Divide all terms by their GCF which is 20 and so w^2+5w+2 which when factored is (m+4.5616)(m+0.4384) to four decimal places A more accurate answer can be found by using the quadratic equation formula
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