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What is the quadratic for x2-13x plus 40?
Assume this quadratic equation equals zero. Then :-x2 - 13x + 40 = 0, this can be factored (x - 8)(x - 5) = 0This holds true when either x - 8 = 0 or x - 5 = 0When x - 8 = 0 then x = 8 : When x - 5 = 0 then x = 5
What is the quadratic equation for x2-13x plus 40?
You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5) that would be 8 and 5 If you want to use the quadratic equation to solve it instead of factoring, the equation is x = (-b + or - the square root of (b2- 4ac))/2a a in this case is 1, b is 13, and c is 40 So, plug a, b, and c into the above equation and do it once with adding and once with subtracting. There will be two x values given if you do it both times, 8 and 5.
What binomial is a factor of the trinomial x2-13x plus 40?
(x - 5)(x - 8)
What is the factorization of the trinomial- x3 plus 13x2 plus 40x?
X3 + 13X2 + 40X factor out an X X(X2 + 13X + 40) factor the quadratic expression, what two factors of 40 add up to 13? X(X + 8)(X + 5) works the same if that is a negative in front of X3, just sign changes
What equation can equal 14 and 40?
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
What is the quadratic for x2-13x plus 40?
Assume this quadratic equation equals zero. Then :-x2 - 13x + 40 = 0, this can be factored (x - 8)(x - 5) = 0This holds true when either x - 8 = 0 or x - 5 = 0When x - 8 = 0 then x = 8 : When x - 5 = 0 then x = 5
What is the quadratic equation for x2-13x plus 40?
You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5) that would be 8 and 5 If you want to use the quadratic equation to solve it instead of factoring, the equation is x = (-b + or - the square root of (b2- 4ac))/2a a in this case is 1, b is 13, and c is 40 So, plug a, b, and c into the above equation and do it once with adding and once with subtracting. There will be two x values given if you do it both times, 8 and 5.
What is the answer to x2 plus 13x-40?
X2 + 13X - 40 = 0I can't factor this, so the quadratic equation will be used.X = - b (+/-) sqrt(b2 - 4ac)/2aa = 1b = 13c = - 40X = - 13 (+/-) sqrt[(132 - 4(1)(- 40)]/2(1)X = - 13 (+/-) sqrt(169 + 160)/2X = [- 13 (+/-) sqrt(329)]/2=========================ugly exact answerInexact answers.X = ~ 2.569X = ~ - 15.569
Factor x² plus 13x plus 40?
x2 + 13x + 40 = x2 + 5x + 8x + 40 = x(x + 5) + 8(x + 5) = (x + 8)(x + 5)
What is the factorization of -x2-13x-40?
-x^2 -13x -40 = -(x^2 + 13x + 40) = -(x + 5)*(x + 8)-x^2 -13x -40 = -(x^2 + 13x + 40) = -(x + 5)*(x + 8)-x^2 -13x -40 = -(x^2 + 13x + 40) = -(x + 5)*(x + 8)-x^2 -13x -40 = -(x^2 + 13x + 40) = -(x + 5)*(x + 8)
What binomial is a factor of the trinomial x2-13x plus 40?
(x - 5)(x - 8)
What is the factorization of the trinomial- x3 plus 13x2 plus 40x?
X3 + 13X2 + 40X factor out an X X(X2 + 13X + 40) factor the quadratic expression, what two factors of 40 add up to 13? X(X + 8)(X + 5) works the same if that is a negative in front of X3, just sign changes
What equation can equal 14 and 40?
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
Factor the trinomial x2 plus 13x plus 40?
You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5)
Factor the trinomial below Enter each factor as a polynomial in descending order x2 plus 13x plus 40?
(x + 5)(x + 8)
What two numbers multipy together equal 40 and add together equal 16?
56
Factor out 6x2 plus 17x plus 40?
This doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (-17 plus or minus the square root of -671) divided by 12x = -1.4166 + 2.158638974498103ix = -1.4166 - 2.158638974498103iwhere i is the square root of negative one.
