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Assume this quadratic equation equals zero. Then :-x2 - 13x + 40 = 0, this can be factored (x - 8)(x - 5) = 0This holds true when either x - 8 = 0 or x - 5 = 0When x - 8 = 0 then x = 8 : When x - 5 = 0 then x = 5
You should look for two numbers whose product is 40, and whose sum is 13. Experimenting a little (trying different pairs of factors for 40), you can quickly realize that this works for 8 and 5. Therefore, x2 + 13x + 40 = (x + 8) (x + 5) that would be 8 and 5 If you want to use the quadratic equation to solve it instead of factoring, the equation is x = (-b + or - the square root of (b2- 4ac))/2a a in this case is 1, b is 13, and c is 40 So, plug a, b, and c into the above equation and do it once with adding and once with subtracting. There will be two x values given if you do it both times, 8 and 5.
(x - 5)(x - 8)
A quadratic equation in the form of: x2-54x+560 = 0 whose solutions are x = 14 and x = 40
X3 + 13X2 + 40X factor out an X X(X2 + 13X + 40) factor the quadratic expression, what two factors of 40 add up to 13? X(X + 8)(X + 5) works the same if that is a negative in front of X3, just sign changes