First of all you have omitted the sign between x^(2) & 12x
However, here is a quadratic that will satisfy
x^2 + 12x - 64 = 0
This will factor to
(x + 16)(x - 4) = 0
x - -16
& x = 4
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With the help of the quadratic equation formula
(x - 1)(x - 11) x = 1,11
x2-12x+20=0you can factor this equation into:(x-10)(x-2)=0set each factor equal to zero & solve for x to get:x=10 & x=2
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.