With the help of the quadratic equation formula
(x - 1)(x - 11) x = 1,11
x2-12x+20=0you can factor this equation into:(x-10)(x-2)=0set each factor equal to zero & solve for x to get:x=10 & x=2
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
It is x = +/- 2 depending on whether the second term in the equation is -12x or +12x.
x2 - 12x + 35
With the help of the quadratic equation formula
(x - 1)(x - 11) x = 1,11
Do you mean 8x2+12x+28?? If so, plug 8,12, and 28 into a,b, and c of this website http://www.math-booster.com/calculators/quadratic-formula.html the answer is imaginary or No Solution
x2-12x+20=0you can factor this equation into:(x-10)(x-2)=0set each factor equal to zero & solve for x to get:x=10 & x=2
=>2x - 12x + 36 = 0 =>10x = 36=>x = 3.6Another contributor's answer:This is a quadratic equation question:x2-12x+36 = 0When factorised:(x-6)(x-6) = 0
It can't be solved because the discriminant of the given quadratic equation is less than zero meaning it has no real roots.
That looks like a linear equation (no quadratic or higher terms), so you can expect it to have a single solution. However, actually solving the equation is not difficult; do it, to confirm this.
(x - 16)(x + 4) = 0 so x = -4 or 16
2x2-12x-54 = 0 Solve by factoring or using the quadratic equation formula or by completing the square: (2x+6)(x-9) = 0 Therefore: x = -3 or x = 9
If you mean: x2+12x+35 then it is a quadratic expression that can be factored as: (x+5)(x+7)