x2 - 12x + 35
x2 + 12x + 32 = (x + 8)(x + 4)
x3 - 12x2 + 35x = x(x2 - 12x + 35) = x(x - 5)(x - 7)
x2+12x+36=0 2x+12x+36=0 14x+36=0 14x=-36 x=-36/14 x=-2 4/7
x + 12x + 20 = (x + 10)(x + 2)
If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)
x2-12x+35 = (x-5)(x-7)
If you mean: x2-12x+35 then it is (x-7)(x-5) when factored
x2 - 12x + 35
An equation demonstrates the equality of two expressions. x2+12x+13 is only one expression. For example, x+y : expression, not equation x+5 = 3 : equation
(x + 7)(x + 5)
x2 - 12x + 36 = (x - 6)2
x2+12x+28Improved Answer:--x2+12x+28 = (-x+14)(x+2) when factored
x2-12x+36 = (x-6)2
x2+12x+5 = 3 x2+12x+5-3 = 0 x2+12x+2 = 0
Factor: x3 - 12x2 + 35x 1. Factor out a x: x(x2 - 12x + 35). 2. Factor x2 - 12x + 35 which is (x-5)(x-7). 3. Answer: x(x-5)(x-7).
x2 + 12x - 11 = x2 + 12x + (12/2)2 - (12/2)2 - 11 = (x + 6)2 - 47