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What is the quotient in polynomial form -1 2 7 5 A. x plus 5 B. x - 5 C. 2x - 5 D. 2x plus 5?
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How do you factor C squared X plus C squared Y?
C2x + C2y = C2(x + y)
What is the x-intercept of 2x plus 8y equals 40?
This form needed. Y = mX + c2X + 8Y = 408Y = - 2X + 40Y = - 1/4 + 5-----------------------zero out the Y- 1/4X + 5 = 0- 1/4X = - 5X = 20-------------------your X intercept
What is the x and y intercepts for 2x-3y24?
Put in this form. Y = mX + c2X - 3Y = 24- 3Y = - 2X + 24Y = 2/3X - 8-------------------zero out variables in turn2/3X - 8 = 02/3X = 8X = 12--------------------X interceptY = 2/3(0) - 8Y = - 8------------------------Y intercept(12, - 8)------------------answer
How do you factor C squared X plus C squared Y?
C2x + C2y = C2(x + y)
What is the x-intercept of 2x plus 8y equals 40?
This form needed. Y = mX + c2X + 8Y = 408Y = - 2X + 40Y = - 1/4 + 5-----------------------zero out the Y- 1/4X + 5 = 0- 1/4X = - 5X = 20-------------------your X intercept
Which point lies on 2x plus 5y equals 10?
First, in this form. Y =mX + c2X + 5Y = 105Y = - 2X + 10Y = (-2/5)X + 2Y = 2----------0 out equation(- 2/5)X + 2 = 0(- 2/5)X = - 2X = 5---------(0, 2) and (5, 0)------------------------------ points on the line
What is the x and y intercepts for 2x-3y24?
Put in this form. Y = mX + c2X - 3Y = 24- 3Y = - 2X + 24Y = 2/3X - 8-------------------zero out variables in turn2/3X - 8 = 02/3X = 8X = 12--------------------X interceptY = 2/3(0) - 8Y = - 8------------------------Y intercept(12, - 8)------------------answer
What is the equation written in standard form of 2X - y - 8 equals 0?
The equation 2X - y - 8 = 0 can be rearranged into standard form as 2X - y = 8. In standard form, the variables are typically placed on the left side of the equation with the constant on the right, without any x or y terms on the same side as the constant.
Is it ok to use the same random number again while signing two messages m1 and m2 using schnorr signature?
Ok here is the answer u r looking for. You cannot use the same random number twice because it will lead the adversary in to finding the secret key x.For the first time r1 = gk1 mod pc1 = H(m1,r1)s1 = k1 + c1x (mod q)----- eqn 1output is (r1, s1,m1)For the second time r1 = r2 = gk1 mod p c2 = H(m2,r1) s2 = k1 + c2x (mod q)-----eqn 2 output is (r1, s2, m2)eqn1-eqn2 s1-s2=c1x (mod q) - c2x (mod q) s1-s2=x modq (c1- c2) x mod q = s1-s2/c1-c2 s1,s2,c1,c2 and q are known.
How would you Write an equation that passes through the point 6 5 and is parallel to the line whose equation is 2x 3y equals 11?
ax+by=c2x+3y=113y=-2x+11(3y=-2x+11)/3= y=-2/3x+11/3 slope intercept form5=-2/3(6)+b replace x and y with point given5=-4+b9=bthereforey=-2/3x+92x+3y=27
What is the slope of the line that is perpendicular to the line whose equation is 2x y 4?
The product of the slope of a line with the slope of a line perpendicular to it is -1.Or to put it another way, if a line has an equationy = mx + ca line perpendicular to it will have a gradient m' such thatmm' = -1⇒ m' = -1/mand an equation ofy = -1/m x + bwhich can be rearranged to givemy + x = d(where d = mb).There are symbols missing from the question, which I suspect are a plus (+) and an equals (=). They can be inserted in two different ways, leading to two different solutions:2x + y = 4⇒ y = -2x + 4 ⇒ gradient of perpendicular line is -1/-2 = 1/2⇒ perpendicular line is:y = 1/2 x + b⇒ 2y = x + c2x = y + 4⇒ y = 2x - 4 ⇒ gradient of perpendicular line is -1/2 = -1/2⇒ perpendicular line is:y = -1/2 x + b⇒ 2y + x = cNote: there is no one perpendicular line, the value of the constant c will vary depending upon what point the line must pass through.
