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If music CD is 2.5 inches in radius what is circumference?
The CD's circumference is 15.7 inches.
Find the circumference of a CD radius of 6 cm?
Multiply the radius by 2 x pi.
Can you find the circumference of a CD that has a radius of 6 centimeters?
nfughs
How many inches is 377mm?
There are 25.4 millimetres in one inch. Therefore, rounded to two decimal places, 377 millimetres is equal to 377 / 25.4 = 14.84 inches.
Is radius half radius?
No. Radius is half of the diameter.
What is the radius of a CD?
The diameter of a CD is 11.43 so the radius is 5.715.
What is radius of a CD or DVD?
The diameter of a CD is about 12 cm, so since the radius is 1/2 of the diameter, that would make the radius about 6 cm. 5.23 cm
If music CD is 2.5 inches in radius what is circumference?
The CD's circumference is 15.7 inches.
Find the circumference of a CD radius of 6 cm?
Multiply the radius by 2 x pi.
A CD has a radius of 6 cm Which is its diameter?
The radius of a circle is the distance from the centre to the edge. The diameter is the distance right across the circle through the centre. So the diameter of a circle is always twice its radius. So if the radius of a circular CD is 6cm, the diameter is twice this - 12cm.
Can you find the circumference of a CD that has a radius of 6 centimeters?
nfughs
What is the size of the CD?
a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
Where canI get the best CD Rates within a l00 mile radius?
Bank of America in Alma has 3.2% 5-year CD that is easily the best around. Consider getting a CD with them.
How much data does a CD hold?
a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
How many inches is 377mm?
There are 25.4 millimetres in one inch. Therefore, rounded to two decimal places, 377 millimetres is equal to 377 / 25.4 = 14.84 inches.
Given radius and chord length. What is the height of arc to midpoint of chord?
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
How do you find the diameter if i have the circumference?
Radius: rDiameter: dCircumference: Cd = 2rC = 2 Pi r = Pi dWhat_is_the_formula_for_finding_diameterSo make it c=Pi*dd=c/Pi
