Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
C = Pi * d 28.26 cm = 3.1415 * d d = 28.26 cm/3.1415 d = 8.9954 r = d/2 r = 8.9954 cm/2 4.4977 cm The radius of a CD with a circumference of 28.26 cm is about 4.50 cm.
A regular CD has a diameter of about 4.75 inches, which means it has a radius of about 2.375 inches. The area of a circle is calculated using the formula A = πr^2, so the area of a regular CD is approximately 17.67 square inches. So, there you have it, the sassy answer to your CD area question.
It means to multiply the radius by itself: radius x radius
When you try to figure out an area of a circle, you square the radius, then multiply it by pi to get the area of a circle. A radius square is radius x radius, or radius squared.
The diameter of a CD is about 12 cm, so since the radius is 1/2 of the diameter, that would make the radius about 6 cm. 5.23 cm
The CD's circumference is 15.7 inches.
Multiply the radius by 2 x pi.
The radius of a circle is the distance from the centre to the edge. The diameter is the distance right across the circle through the centre. So the diameter of a circle is always twice its radius. So if the radius of a circular CD is 6cm, the diameter is twice this - 12cm.
if perimeter of cd=377mm perimeter of circle cd=2x22/7xr Using pie as 22/7 radius=> 2x22/7xr=377mm r= 120.0636943 r= 60.03184713mm -Keran Persaud Basiram
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a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
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a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
Radius: rDiameter: dCircumference: Cd = 2rC = 2 Pi r = Pi dWhat_is_the_formula_for_finding_diameterSo make it c=Pi*dd=c/Pi
When a cadmium atom becomes a cadmium ion, it loses two electrons to achieve a stable electron configuration. This loss of electrons changes the charge of the cadmium atom from neutral to a 2+ charge, resulting in the formation of a positively charged ion.