The diameter of a CD is 11.43 so the radius is 5.715.
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
C = Pi * d 28.26 cm = 3.1415 * d d = 28.26 cm/3.1415 d = 8.9954 r = d/2 r = 8.9954 cm/2 4.4977 cm The radius of a CD with a circumference of 28.26 cm is about 4.50 cm.
Standard CDs have a diameter of 120 mm; that would be a radius of 60 mm. Since area is calculated as the value of pi (3.1416) times the square of the radius, we calculate as follows: Area A = pi X r2 = 3.1416 X 60 mm X 60 mm = 3.1416 X 3600 mm2 = 11,309.76 mm2. That value translates to 113.0976 square centimeters or 17.5301631 square inches. The area just calculated includes the hole. If you wish the hole excluded, so you have just the surface area of the disk, subtract the area of the hole, which has a diameter of 15 mm. The hole, with a radius of 7.5 mm, has an area of 176.715 mm2. Subtracting that from the area of a circle with a 120 mm diameter (11,309.76 mm2), we get a true surface area of 11,133.045 mm2 or 17.2562543 in2.
It means to multiply the radius by itself: radius x radius
When you try to figure out an area of a circle, you square the radius, then multiply it by pi to get the area of a circle. A radius square is radius x radius, or radius squared.
The diameter of a CD is about 12 cm, so since the radius is 1/2 of the diameter, that would make the radius about 6 cm. 5.23 cm
The CD's circumference is 15.7 inches.
Multiply the radius by 2 x pi.
The radius of a circle is the distance from the centre to the edge. The diameter is the distance right across the circle through the centre. So the diameter of a circle is always twice its radius. So if the radius of a circular CD is 6cm, the diameter is twice this - 12cm.
if perimeter of cd=377mm perimeter of circle cd=2x22/7xr Using pie as 22/7 radius=> 2x22/7xr=377mm r= 120.0636943 r= 60.03184713mm -Keran Persaud Basiram
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a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
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a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
Radius: rDiameter: dCircumference: Cd = 2rC = 2 Pi r = Pi dWhat_is_the_formula_for_finding_diameterSo make it c=Pi*dd=c/Pi
When a cadmium atom becomes a cadmium ion, it loses two electrons to achieve a stable electron configuration. This loss of electrons changes the charge of the cadmium atom from neutral to a 2+ charge, resulting in the formation of a positively charged ion.