The diameter of a CD is 11.43 so the radius is 5.715.
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
C = Pi * d 28.26 cm = 3.1415 * d d = 28.26 cm/3.1415 d = 8.9954 r = d/2 r = 8.9954 cm/2 4.4977 cm The radius of a CD with a circumference of 28.26 cm is about 4.50 cm.
It means to multiply the radius by itself: radius x radius
When you try to figure out an area of a circle, you square the radius, then multiply it by pi to get the area of a circle. A radius square is radius x radius, or radius squared.
The diameter is twice the radius. So multiply the radius by 2
The diameter of a CD is about 12 cm, so since the radius is 1/2 of the diameter, that would make the radius about 6 cm. 5.23 cm
The CD's circumference is 15.7 inches.
Multiply the radius by 2 x pi.
The radius of a circle is the distance from the centre to the edge. The diameter is the distance right across the circle through the centre. So the diameter of a circle is always twice its radius. So if the radius of a circular CD is 6cm, the diameter is twice this - 12cm.
if perimeter of cd=377mm perimeter of circle cd=2x22/7xr Using pie as 22/7 radius=> 2x22/7xr=377mm r= 120.0636943 r= 60.03184713mm -Keran Persaud Basiram
nfughs
a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
Bank of America in Alma has 3.2% 5-year CD that is easily the best around. Consider getting a CD with them.
a CD is 120mm (4.7 inches) in diameter and 60mm radius, the hole is 15mm diamter (0.6 inches).
the cadmium atom looses two electrons and its radius decreases because by taking away two electrons (negatively charged) it makes the nucleus positive with a positive 2 charge. since theres two less electrons the radius is smaller. hope i helped :D
Draw the circle O, and the chord AB. From the center, draw the radius OC which passes though the midpoint, D, of AB. Since the radius OC bisects the chord AB, it is perpendicular to AB. So that CD is the required height, whose length equals to the difference of the length of the radius OC and the length of its part OD. Draw the radius OA and OB. So that OD is the median and the height of the isosceles triangle AOB, whose length equals to √(r2 - AB2/4) (by the Pythagorean theorem). Thus, the length of CD equals to r - √(r2 - AB2/4).
Radius: rDiameter: dCircumference: Cd = 2rC = 2 Pi r = Pi dWhat_is_the_formula_for_finding_diameterSo make it c=Pi*dd=c/Pi