Radius is 3. Here is how: So you need to get two "square expressions". So there are y^2 but no y. So we have y^2. Then we have x^2 + 4x + (something). A perfect square is (x + 2)^2 = x^2 + 4x + 4. So we need to add 4 to both sides and we have x^2 + 4x + 4 + y^2 = 9. Or (x + 2)^2 + y^2 = 3^2. The radius is 3.
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
No.
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
x^2+4x+7
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
y = 4x-3
x2+4x+4 = 25 x2+4x+4-25 = 0 x2+4x-21 = 0 (x+7)(x-3) = 0 x = -7 or x = 3
No.
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
x^2+4x+7
2x = x2 + 4x - 3 x2 + 2x - 3 = 0 (x - 1)(x - 2) = 0
X2 or 2 times x?
7
x2 + 4x + 3 = 0 (x + 1)(x + 3) = 0 x ∈ {-3, -1}
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
y=-x^2+4x-3
Y = x2 + 4x + 11OK. That's very interesting.Is there a question ?