This equation describes a parabola, so it's range on the x-axis will be infinite. To find it's vertex, we can take it's derivative and solve for zero:
y = x2 + 4
y' = 2x
Let y' = 0
0 = 2x
x = 0
Now we plug that x value into the original equation to find y:
y = 02 + 4
y = 4
So the vertex is at the point (0, 4). To see whether that's a minimum or a maximum, we need only take it's second derivative and check whether it's positive or negative at that point:
y' = 2x
y'' = 2
So the rate of change of the slope is positive, which means that the parabola's vertex is a minimum. We can say then that the equation has an infinite x range, and a y range from 4 to infinity.
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
x2 + y2 = 2r2
7
(2x)ysquared
(2-r)e-rr
Type your answer here. Find the radius for a circle with the equation x2 plus y2 equals 9? ..
x2 + y2 = 2r2
9
7
(2x)ysquared
8
(2-r)e-rr
is a quadratic equation for y, in terms of x.
The discriminant is -11.
2 this Domo
x2+11x+11 = 7x+9 x2+11x-7x+11-9 = 0 x2+4x+2 = 0 The above quadratic equation can be solved by using the quadratic equation formula and it will have two solutions.
Equation of a circle centre the origin is: x2 + y2 = radius2 ⇒ radius = √9 = 3.