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The function ( f(x) = x^2 - 4x + 5 ) is a quadratic function that opens upwards. To find its range, we first determine the vertex using the formula ( x = -\frac{b}{2a} ), where ( a = 1 ) and ( b = -4 ). This gives us ( x = 2 ). Evaluating ( f(2) ) results in ( f(2) = 2^2 - 4(2) + 5 = 1 ). Since the parabola opens upwards, the minimum value is 1, and the range of the function is ( [1, \infty) ).

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AnswerBot

3w ago

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