range of y=sin(2x) is [-1;1]
and in generally when is y=sin(k*x) (k=....-1,0,1....) range is always [-1;1] and the period is w=(2pi)/k
dy/dx = 2cos2x
The range of y=2x is All Real Numbers
sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!
y=|x|/4 The range is [0 , ∞ )
The range depends on the domain, which is not specified.
dy/dx = 2cos2x
Sin2x = radical 2
y=1/sinxy'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)y'=(sinx*0-1(cosx))/(sin2x)y'=(-cosx)/(sin2x)y'=-(cosx/sinx)*(1/sinx)y'=-cotx*cscx
The range of y=2x is All Real Numbers
If you mean y =9x^2 -4 , than the range is the possible y values. Range = 0<= y < infinity.
sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!
y=|x|/4 The range is [0 , ∞ )
The proof of this trig identity relies on the pythagorean trig identity, the most famous trig identity of all time: sin2x + cos2x = 1, or 1 - cos2x = sin2x. 1 + cot2x = csc2x 1 = csc2x - cot2x 1 = 1/sin2x - cos2x/sin2x 1 = (1 - cos2x)/sin2x ...using the pythagorean trig identity... 1 = sin2x/sin2x 1 = 1 So this is less of a proof and more of a verification.
The range depends on the domain, which is not specified.
The range depends on the domain.
-4
The function y=x is a straight line. The range is all real numbers.