range of y=sin(2x) is [-1;1]
and in generally when is y=sin(k*x) (k=....-1,0,1....) range is always [-1;1] and the period is w=(2pi)/k
dy/dx = 2cos2x
The range of y=2x is All Real Numbers
y=|x|/4 The range is [0 , ∞ )
The range depends on the domain, which is not specified.
sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!
dy/dx = 2cos2x
Sin2x = radical 2
y=1/sinxy'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)y'=(sinx*0-1(cosx))/(sin2x)y'=(-cosx)/(sin2x)y'=-(cosx/sinx)*(1/sinx)y'=-cotx*cscx
The range of y=2x is All Real Numbers
If you mean y =9x^2 -4 , than the range is the possible y values. Range = 0<= y < infinity.
y=|x|/4 The range is [0 , ∞ )
sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!
The range depends on the domain.
The range depends on the domain, which is not specified.
The proof of this trig identity relies on the pythagorean trig identity, the most famous trig identity of all time: sin2x + cos2x = 1, or 1 - cos2x = sin2x. 1 + cot2x = csc2x 1 = csc2x - cot2x 1 = 1/sin2x - cos2x/sin2x 1 = (1 - cos2x)/sin2x ...using the pythagorean trig identity... 1 = sin2x/sin2x 1 = 1 So this is less of a proof and more of a verification.
The function y=x is a straight line. The range is all real numbers.
The domain is the x values, so x = 0 to 10. The range is the y values, so y = 0 to 25.