dy/dx = 2cos2x
The range of y=2x is All Real Numbers
sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!
y=|x|/4 The range is [0 , ∞ )
The range depends on the domain, which is not specified.
dy/dx = 2cos2x
Sin2x = radical 2
y=1/sinxy'=(sinx*d/dx(1)-1*d/dx(sinx))/(sin2x)y'=(sinx*0-1(cosx))/(sin2x)y'=(-cosx)/(sin2x)y'=-(cosx/sinx)*(1/sinx)y'=-cotx*cscx
The range of y=2x is All Real Numbers
If you mean y =9x^2 -4 , than the range is the possible y values. Range = 0<= y < infinity.
sin2X = sin2X What is it about ' equation ' you do you not understand. Of course they are equal!
y=|x|/4 The range is [0 , ∞ )
The range depends on the domain, which is not specified.
The range depends on the domain.
The proof of this trig identity relies on the pythagorean trig identity, the most famous trig identity of all time: sin2x + cos2x = 1, or 1 - cos2x = sin2x. 1 + cot2x = csc2x 1 = csc2x - cot2x 1 = 1/sin2x - cos2x/sin2x 1 = (1 - cos2x)/sin2x ...using the pythagorean trig identity... 1 = sin2x/sin2x 1 = 1 So this is less of a proof and more of a verification.
The function y=x is a straight line. The range is all real numbers.
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