The amplitude of the wave [ y = -2 sin(x) ] is 2.
You need to know the trigonometric formulae for sin and cos of compound angles. sin(x+y) = sin(x)*cos(y)+cos(x)*sin(y) and cos(x+y) = cos(x)*cos(y) - sin(x)*sin(y) Using these, y = x implies that sin(2x) = sin(x+x) = 2*sin(x)cos(x) and cos(2x) = cos(x+x) = cos^2(x) - sin^2(x) Next, the triple angle formulae are: sin(3x) = sin(2x + x) = 3*sin(x) - 4*sin^3(x) and cos(3x) = 4*cos^3(x) - 3*cos(x) Then the left hand side = 2*[3*sin(x) - 4*sin^3(x)]/sin(x) + 2*[4*cos^3(x) - 3*cos(x)]/cos(x) = 6 - 8*sin^2(x) + 8cos^2(x) - 6 = 8*[cos^2(x) - sin^2(x)] = 8*cos(2x) = right hand side.
x = (2n+1)*pi/2 radians for any integer n.
The period of the function y= tan(x) is pie The periods of the functions y= cos(x) and y= sin(x) is 2pie
f(x) = 1/x except where x = 0.
range of y=sin(2x) is [-1;1] and in generally when is y=sin(k*x) (k=....-1,0,1....) range is always [-1;1] and the period is w=(2pi)/k
Assuming a large enough domain, the range is -1 to 1.
If x = sin θ and y = cos θ then: sin² θ + cos² θ = 1 → x² + y² = 1 → x² = 1 - y²
sin x can have any value between -1 and 1; therefore, 3 sin x has three times this range (from -3 to 3).
the range is greater then -1 but less than 1 -1<r<1
Y=sin X is a function because for each value of X, there is exactly one Y value.
sin(pi) = 0 so 4*sin(pi) = 0 so Y = 0
The amplitude of the wave [ y = -2 sin(x) ] is 2.
D(y)= sin 2x
It is zero.
y=3 cos(x) y' = -3 sin(x)
y=-10 sin 5x sin 5x=y/-10 x=asin(y/-10)/5