95 - 50 = 45
The mean is now: (74+76+77+78+79+80+80+82+84)/9 = 78.889. Since 50 is an outlier, the overall representation of the test score becomes more accurate since the majority of values lie between 74 and 84.
78 rounded to the nearest ten is 80
80
2 + 78 = 80
51, 54, 57, 60, 63, 66, 69, 72, 75, 78
The mean is now: (74+76+77+78+79+80+80+82+84)/9 = 78.889. Since 50 is an outlier, the overall representation of the test score becomes more accurate since the majority of values lie between 74 and 84.
(75+83+78+X)/4=80, solve for X X=4*80-75-83-78 So X=84
78% of 80 people= 78% * 80= 0.78 * 80= 62.4 people
80
They are in the range of 50 to 80 dolars
80 is 2 bigger than 78
First, you probably need more than one raw score. If you only have one raw score then your range is one point, the (score - 1/2) to the (score + 1/2). For a score of 80, the range would be from 79.5 to 80.5. It is kind of meaningless if you find a range for just one score. You need a larger sample size. A better question is: "How do I find the range of a sample of raw scores?" You need all of the raw scores in your sample, not just one score. Because each whole number (i.e., 80) represents a continuum (e.g., of ability), the range goes from 1/2 a point below the lowest score to 1/2 a point above the highest score. Let's look at some fake data with 5 participants: 10 20 30 40 50. The highest score is 50. The lowest score is 10. The range is (10-.5) to (50+.5). The range of raw scores is 9.5 to 50.5, a range of 41 points. If you are looking for the easy answer, then the range is 10 to 50 (lowest score to highest score; a range of 40 points). If you for some reason only have one score (e.g., 80), the long answer is 79.5 to 80.5 (range of one), the short answer is that there is no variability (range of zero).
78 rounded to the nearest ten is 80
The composite numbers between 50 and 80 are: 50, 51, 52, 54, 55, 56, 57, 58, 60 62, 63, 64, 65, 66, 68, 69, 70, 72 74, 75, 76, 77, 78, 80
Total scores of the 35 juniors = 35 x 80 = 2800 Total scores of the 15 seniors = 15 x 70 = 1050 Combined total score = 2800 + 1050 = 3850 Average or arithmetic mean of the set of 50 students = 3850 ÷ 50 = 77.
80
The GCF of 80, 78, and 2 is 2.