272 percent as a fraction in simplest form is 68/25
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
272% as a mixed number is 218/25
sqrt(272) = sqrt(16*17) = 4*sqrt(17)
the value of the exponent n1
The turns ratio of a transformer is the number of primary turns to secondary turns. This defines how the transformer will change the voltage and current. For N1 primary turns, and N2 secondary turns, N1/N2 will be the turns ratio; the secondary voltage will be:the primary voltage x (N2/N1); The secondary current will be:primary current x (N1/N2)
i think ... at first measure V and I and then use the formula > N1/N1 = V1/V2 = I2/I1 to calculate N
You can't, unless you have a crazy tap changer so you can remove or add windings to change the ratio from N1 > N2 to N2 > N1.
272 percent as a fraction in simplest form is 68/25
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
272% as a mixed number is 218/25
sqrt(272) = sqrt(16*17) = 4*sqrt(17)
P(x=n1,y=n2) = (n!/n1!*n2!*(n-n1-n2)) * p1^n1*p2^n2*(1-p1-p2) where n1,n2=0,1,2,....n n1+n2<=n
#include<stdio.h> int main(){ int n1,n2; printf("\nEnter two numbers:"); scanf("%d %d",&n1,&n2); while(n1!=n2){ if(n1>=n2-1) n1=n1-n2; else n2=n2-n1; } printf("\nGCD=%d",n1); return 0; }
the value of the exponent n1
the value of the exponent n1
9/8