Let a + bi be the reciprocal. So (a + bi)(2 - 5i) = 1 (a + bi)(2 - 5i) = 2a - 5ai + 2bi + 5b = (2a + 5b) + (2b - 5a)i Therefore 2a + 5b = 1 and 2b - 5a = 0. Solving the simultaneous equations, we find that a = 2/29 and b = 5/29. So the reciprocal of 2 - 5i is 2/29 + 5i/29.
Since the question is 3(2a), then just write it out. 3(2a) is 2a+2a+2a or 6a.
The multiplicative inverse of -2a is 1/(-2a) = -1/2a
2a+2a-7b+7b =4a
a-^2a-b^-a-b
The answer is 4a^2.
a + a + a - 2a = 3a - 2a = a
2a + 2b = c subtract 2a from both sides 2a - 2a + 2b = c - 2a 2b = c - 2a divide both sides by 2 (2/2)b = (c - 2a)/2 b = (c - 2a)/2 --------------------
8b36
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3a-2a = 1
9a +8 -2a -3 -5a = 2a +5