a-2b is a binomial. It has two terms: a, and -2b.
(a + 2b)(a + 2b)
12c + 2b
7 over 7 = 1 Then -2b divided by 1 = -2b
The simplified answer is: 4c+2b
Let a + bi be the reciprocal. So (a + bi)(2 - 5i) = 1 (a + bi)(2 - 5i) = 2a - 5ai + 2bi + 5b = (2a + 5b) + (2b - 5a)i Therefore 2a + 5b = 1 and 2b - 5a = 0. Solving the simultaneous equations, we find that a = 2/29 and b = 5/29. So the reciprocal of 2 - 5i is 2/29 + 5i/29.
18h+4b-2b
=2b
a-2b is a binomial. It has two terms: a, and -2b.
a + 2b = c a = c - 2b
2B 2B or not 2B, that is the question.
-b+5b-2b=2b
4a+2b+a
-2b + 7 -3b = 2 -2b +7 -3b +2b = 2 + 2b 7 -3b + 3b = 2 + 2b +3b 7-2 = 2-2 + 2b + 3b 5 = 5b 1 = b
2b -5 = -3
(a + 2b)(a + 2b)
This is the same as: 13-2b = 21 -2b = 21-13 -2b = 8 b = -4